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Zepler [3.9K]
3 years ago
12

Paul needs to buy 5/8 pound of peanuts.The scale at the store measures parts of a pound in sixteenth. What measure is equivalent

to 5/8 pound?
Mathematics
1 answer:
Gemiola [76]3 years ago
5 0
5/8 = 10/16
Since it is measured in 1/16 of a pound.  I converted 5/8  to 10/16.

5    =    10
___      __
 8         16      

Multiplied both top and bottom by 2 to get the 16 as the denominator.


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Use the quadratic formula to solve the equation <br> X^2+9X+20=0
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Step-by-step explanation:

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businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
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Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
The fox population in a certain region has a continuous growth rate of 6 percent per year. It is estimated that the population i
Ksivusya [100]

Answer:

P(t) = 9800(1.06)^t

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Step-by-step explanation:

For growth the equation is

y = ab^x  where a is the initial value, b = 1 plus the growth percentage, and x is the number of years

P(t) = 9800 (1+.06) ^t

P(t) = 9800(1.06)^t

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15619.71113040224768

We can only have whole foxes

P(8) = 15620

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Step-by-step explanation:

4 0
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