Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:
Hence the bounds of the interval are found as follows:
The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
Answer:
John spent around $53
Step-by-step explanation:
The equation is 3x=160
Since the "x" is already by itself on one side, divide 160 by 3
160÷3=53.333⇒
Now if that's not the way IT CAN ALSO BE:
30x3+70=160! That means John spent $90
The correct answer for the question that is being presented above is this one: "0.5" <span>The probability that a normal random variable is less than its mean is 0.5. In a normal distribution, 1.0 refers to the one that is stable and is in equilibrium.</span>
did you find the answers :( ??
Y= -75x +1725
y= -75(20) +1725
y = -1500 + 1725
y= 225 = range
225= -75x +1725
225 - 1725= -75x
-1500=-75x
-1500/-75 = -75x/-75
x = 20 = domain
