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mina [271]
4 years ago
10

select the name of the polygon. then select whether it is a regular polygon or not a regular polygon.

Mathematics
1 answer:
atroni [7]4 years ago
3 0

Answer:

Step-by-step explanation:

Hexagon

Irregular

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Someone please help me!!!!
Sunny_sXe [5.5K]

Answer:

180+54sqrt3

You have to use the formula that is contained within the lessons, the answer you should have before you format it like this is: 273.530743609

5 0
3 years ago
Plzzzzzz helppppp asappppp <br> ****will mark brainliest ****
Sonja [21]

ΔABC is a 45 - 45 - 90 triangle. The pattern of its sides is as follows:

Each leg = 1 unit (and both legs are that way, since the triangle is isosceles - so two sides are the same)

Hypotenuse = √2 units.

So if we know either leg, we multiply by √2 to get the hypotenuse. In reverse, we divide by √2 if we know the hypotenuse to get the measurement of a leg.

Our problem tells us that the hypotenuse AC is 10 units. We divide 10 by √2 to get the measurement of leg AB. Since it's a 45 -45 - 90 triangle, AB = BC.

AB = \frac{10}{\sqrt{2}}

= \frac{10\sqrt{2}}{\sqrt{2}\sqrt{2}} to rationalize the radical

= \frac{10\sqrt{2}}{2} = 5\sqrt{2}

Thus, each leg is 5\sqrt{2} [/tex].

6 0
3 years ago
The expanded form 900,000 + 40,000 + 300 + 1 represents the whole number.
AleksandrR [38]
900,000+40,000+300+1= 940,301.. The answer is D.)
4 0
4 years ago
Read 2 more answers
There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am
Bas_tet [7]

Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

n = 479, \pi = \frac{130}{479} = 0.2714

Hence the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 - 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.2316

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 + 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.3112

The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
2 years ago
Which expression is equivalent to negative 32 5/3?
Sloan [31]
Im confused. Its not equal to any of the choices

Unless C  is the cube root of 32^5.

 [t3] \sqrt[n]{x} [32^5]
6 0
3 years ago
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