Answer:
There are vertical asymptotes at x: {-1, 0, 5}
Step-by-step explanation:
It's easier (at least for some) if you write this function as
3
F(X) = ------------------
x(x-5)(x+1)
Can you now see that if x = 0, this function is undefined? Same for x = 5 and x = -1? There are vertical asymptotes at x: {-1, 0, 5}
The top answer is correct.
9514 1404 393
Answer:
17 square units
Step-by-step explanation:
There are several ways you can divide this figure into areas that are easily computed.
One that comes to mind is to consider the triangle that would include the missing area at lower right. That triangle would have a base of 6 and a height of 8, so an area of ...
A = (1/2)bh
A = (1/2)(6)(8) = 24 . . . . square units
The part at lower right that is cut out is a sort of reversed L-shape that is 3 squares along the bottom and 4 more up the side, for a total of 7 squares.
Then the area of the shaded part is ...
A = 24 - 7 = 17 . . . . square units
Answer:
33
Step-by-step explanation:
