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3 years ago

What is the slope of the line that passes through the points (14, 5) and (20, –4)? A. -3/2 B. -2/3 C. 2/3 D. 3/2

1 answer:

6 0

The slope of the line that passes through the points (14/5) and (20, -4), so you take y-y/x-x so you substitute the y's in for 5 and -4 and x in for 14 and 20.

5--4/ 14-20
9/-6
Then you make the fraction smaller!
-3/2 = Answer

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14. The prime factorization of a number is

NikAS [45]

Answer:

See below.

Step-by-step explanation:

The number = 5 * 7 * 23.

5 * 7 = 35 must therefore also be a factor.

If we divide the number by 35 we get 23!.

4 0

3 years ago

Maggie creates the fraction models shown to find the value of 1 3/4 divided by 2/3

Assoli18 [71]

Answer: where is them model

Step-by-step explanation:

8 0

3 years ago

Sean bought 8 slurpees at $1.50 each and 6 popsicles. He gave the cashier $25.00 and received $4.00 change. How much did each Po

Lina20 [59]

Answer:

1.50

Step-by-step explanation:

8 x 1.50=12

25-12=13

13-4=9

9/6=1.5

8 0

2 years ago

Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

3 years ago

1 2 3 4 Pls help meee!!!

Rus_ich [418]

Answer:x=2

Step-by-step explanation:

3 0

2 years ago