To solve this problem you must apply the proccedure shown below:
1. You have to r<span>ewrite x=12 in polar form. Then, you have:
12=rCos</span><span>θ
2. Then, you must solve for r, as following:
r=12/Cos</span><span>θ
</span> 3. You have that 1/Cosθ=Sec<span>θ, therefore:
</span> r=12(1/Cos<span>θ)
</span> r=12Sec<span>θ
</span> Therefore, as you can see, the answer is: r=12Secθ<span>
</span>
Answer:
a) ∠BAC corresponds to ∠CDA
Step-by-step explanation:
We assume that the statement ∠BCA ≅ ∠CAD is supposed to mean ΔBCA ~ ΔCAD.
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For any statement about correspondence to be true, the order of the vertex names in the statement must match the order of the vertex names in the similarity claim.
Here, the letters of ∠BAC are the 1st, 3rd, and 2nd letters of the name of the first triangle in the assumed similarity statement. The 1st, 3rd, and 2nd letters in the name of ΔCAD are C, D, A, so corresponding angles are ...
∠BAC and ∠CDA . . . . . matches answer choice A
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<em>Comment on the problem statement</em>
As written here, ∠C in the first triangle corresponds to ∠A in the second triangle. This tells you nothing about the relationships of the other angles or sides. That is why we have to assume a similarity statement is intended. Otherwise, the problem cannot be appropriately answered.
What is the Interquartile range for the following data set?<br>
5,6,7,3,9,8,3,1,6,7,7
Tju [1.3M]
Answer:
4
Step-by-step explanation:
<h3><u>Given</u>:-</h3>
First side(a) of triangle = 17in.
Second side(b) of triangle = 13in.
Perimeter of triangle = 45in.
<h3><u>To Find</u>:-</h3>
Third side of the triangle.
<h3><u>Formula Used</u>:-</h3>
Perimeter of triangle = sum of all side(a+b+c).
<h3><u>Solution</u>:-</h3>
Perimeter of triangle = a + b + c.(putting the value of perimeter, side a and b from the above given)
Therefore, <u>third side = 15in.</u>
<u>To convert this value into feet we need to divide it by 12</u>, because there are 12 inches in a foot.
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Hope it helps you:)
Answer:
2:4 means one part is 2/(2+4)=1/3 of AB and the other part is 2/3 of AB
Step-by-step explanation:
Add 1/3 of the distance from -2 to 4. (1/3)(4+2)=2. -2+2=0 The x coordinate is 0
Subtract 1/3 of the distance from 6 to -6, (1/3)6+6)=4 6-4=2 The y coordinate is 2
The point is (0,2)
Check the answer
distance from (-2,6) to (0,2) is square root of (-2)^2 + (4)^2 = sqr20 = 2(5)^2
distance from (0,2) to (4,-6) is square root of (4)^2 +(8)^2 = sqr80 = 4(5)^2
First distance is half the 2nd distance, so the point divides AB into 2 parts in a ratio of 2:4