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3 years ago

Solve the equation 2√x+1=7-x

Mathematics

1 answer:

BaLLatris [955]3 years ago

6 0

Answer:
x = 8 − 2√7
Explanation: Isolate the radical, then raise each side of the equation to the power of its index.

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What is the solution set of the quadratic inequality x^2+x-2 ≥ 0

hjlf

The answer is the first one

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3 years ago

Find all the polynomials f (t ) of degree ≤ 2 [of the form f (t) = a + bt + ct2] whose graphs run through the points (1, 3) and

Ugo [173]

Answer:

f(t) = 4 - 3t + 2t^2

Step-by-step explanation:

Given:

f(t) = a + bt + ct^2

Differentiate w.r.t. "t"

f'(t) = b + 2ct

1) f(1) = 3

a + b +c = 3...........1)

2) f(2) = 6

a + 2b + 4c = 6.........2)

3) f'(1) = 1

b + 2c = 1 ...............3)

Solving above three simultaneous equations:

a = 4

b = -3

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Therefore equation becomes:

f(t) = 4 + (-3)t + (2)t^2

3 0

3 years ago

Help complete please

Norma-Jean [14]

A: (-3,-1)
B: (4,-5)
C: (-2,3)
D: (1,4)

7 0

3 years ago

Sienna used base-ten blocks to find 45 divide 3

Mice21 [21]

Answer would most likely be quince

7 0

4 years ago

Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation?

Nady [450]

For this case we have the following polynomial:
$x ^ 2 = 12x - 15
$
The first thing to do is to place the variables on the same side of the equation.
We have then:
$x ^ 2 - 12x = -15
$
We complete the square by adding the term (b / 2) ^ 2 on both sides of the equation.
We have then:
$x ^ 2 - 12x + (-12/2) ^ 2 = -15 + (-12/2) ^ 2
$
Rewriting we have:
$x ^ 2 - 12x + (-6) ^ 2 = -15 + (-6) ^ 2

x ^ 2 - 12x + 36 = -15 + 36
 
(x-6) ^ 2 = 21$
$x-6 =+/- \sqrt{21}$
Therefore, the solutions are:
$x = 6 - \sqrt{21}$
$x = 6 + \sqrt{21}$
Answer:
the solution set of the equation is:
$x = 6 - \sqrt{21}$
$x = 6 + \sqrt{21}$

3 0

3 years ago

Read 2 more answers

Solve the equation 2√x+1=7-x​

Solve the equation 2√x+1=7-x