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2 years ago

What is the answer to this 6w+5>2(3w+3).

Mathematics

1 answer:

fomenos2 years ago

8 0

Answer:

No Solution

Step-by-step explanation:

So we have the inequality:

$6w+5>2(3w+3)$

Distribute on the right:

$6w+5>6w+6$

Subtract 6w from both sides:

$5>6$

5 is <em>not</em> greater than 6.

Therefore, the answer to this inequality is no solution.

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Can someone please help me !

kipiarov [429]

Answer:

A = $\frac{5}{6}$

Step-by-step explanation:

From the number line attached in the figure,

Number of small parts from number 0 to 1 on the given number line = 6

A is the point which lies at 5th part from 0.

Each small part represents the fraction = $\frac{1}{6}$

Therefore, A represents the fraction = $5\times \frac{1}{6}$

= $\frac{5}{6}$

So A = $\frac{5}{6}$ will be the answer.

8 0

3 years ago

FOR 15 POINTS I WILL GIVE BRAINLEST IF YOU ARE CORRECT! What is the solution to the system that is created by the equation y = 2

goblinko [34]

The solution point is (4,2).

Step-by-step explanation:

Equation of straight line passing through the points (0,0) and (4,2) is given by

⇒ 2y = x ............ (1)

And the other straight line is y = - x + 6 .............. (2)

Now, solving equations (1) and (2) we get, y = - 2y + 6

⇒ 3y = 6

⇒ y = 2

And from equation (1) we get, x = 2y = 4

Therefore, the solution point is (4,2). (Answer)

6 0

3 years ago

Read 2 more answers

Use the parabola tool to graph the quadratic function f(x)=−12x2+7. Graph the parabola by first plotting its vertex and then plo

Fudgin [204]

First we find the vertex of parabola $f(x)=-12 x^{2} +7$

The vertex of parabola is $( \frac{-b}{2a},f( \frac{-b}{2a}))$
Here,
b = coefficient of x term
a = coefficient of x² term

For given parabola, b = 0 , a = -12

So,
$\frac{-b}{2a}= \frac{0}{-24} =0$

And,

$f( \frac{-b}{2a} )=f(0) = -12(0)+7=7$

Thus the vertex of parabola is (0, 7)

To find another point on parabola, substitute x by 1.

$f(1)=-12( 1^{2}) +7=-12+7=-5$

So the second point on parabola is (1,-5)

The plot of parabola is shown in image below: