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Dahasolnce [82]
2 years ago
9

Which postulate proves these two

Mathematics
1 answer:
jeka57 [31]2 years ago
8 0

Answer:

SAS

Step-by-step explanation:

According to the figure...

<em><u>AB=</u></em><em><u>CD</u></em><em><u>. </u></em><em><u>(</u></em><em><u>side)</u></em><em><u> </u></em><em><u>(</u></em><em><u>given)</u></em>

<em><u>AC=</u></em><em><u>AC </u></em><em><u>(</u></em><em><u>side)</u></em><em><u> </u></em><em><u>(</u></em><em><u>common</u></em><em><u>)</u></em>

<em><u>angle</u></em><em><u> </u></em><em><u>B=</u></em><em><u> </u></em><em><u>angle</u></em><em><u> </u></em><em><u>D </u></em><em><u>(</u></em><em><u>angle</u></em><em><u>)</u></em><em><u> </u></em><em><u>(</u></em><em><u>given</u></em><em><u>)</u></em>

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During a lunch period, a survey is done about the students at LCHS with the following results:
Flauer [41]

Answer:

1 in 47.

Step-by-step explanation:

Add all of the outcomes (28 + 2 + 3 + 14).

You'll get 47.

Do not add the 1s.

There is your answer.

1 in 47.

4 0
3 years ago
A girls hair is 23 inches long how long and grows about half an inch every month how long will her hair be in 2 years
jasenka [17]

Answer:

Step-by-step explanation:

1/2 multiplied by (12 multiplied by 2)

1/2 (24)

= 12 inches grown + 23 inches

= 35 inches long

4 0
3 years ago
Recall that a 6-bit string is a bit strings of length 6, and a bit string of weight 3, say, is one with exactly three 1's. How m
strojnjashka [21]

Answer:

1.. Total number of 6 bit strings is 64

2. Number of 6-bit strings with weight of 0 is 1

3. Number of 6-bit strings with weight of 1 is 6

4. Number of 6-bit strings with weight of 3 is 20

5. Number of 6-bit strings with weight of 5 is 6

6. Number of 6-bit strings with weight of 6 is 1

7. Number of 6-bit strings with weight of 7 is 0

Step-by-step explanation:

A bit string is a string that contains 0 and 1 only

1. Total number of 6 bit strings is 2^6 = 64

2. Number of 6 bit strings with weight 0 is 1

Explanation

Weight 0 means a string with no occurrence of 1

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 0 i.e. no occurrence of 1

6C0 = 6!/(6-0)!0!

6C0 = 6!/6!0!

6C0 = 1

Hence, the number of string with weight 0 (i.e. no occurrence of 1 ) is 1

3. Number of string with weight 1 is 6

Explanation

Weight 0 means a string with exactly 1 occurrence of '1'

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 1

6C1 = 6!/(6-1)!1!

6C1 = 6!/5!1!

6C1 = 6

Hence, the number of string with weight 6

4. Number of string with weight 3 is 20

Explanation

n = 6 and r = 3

6C3 = 6!/(6-3)!3!

6C3 = 6!/3!3!

6C3 = 20

Hence, the number of string with weight 3 is 20

5. Number of string with weight 5 is 6

Explanation

n = 6 and r = 5

6C5 = 6!/(6-5)!5!

6C5 = 6!/1!5!

6C5 = 6

Hence, the number of string with weight 5 is 6

6. Number of string with weight 6 is 1

Explanation

n = 6 and r = 6

6C6 = 6!/(6-6)!6!

6C6 = 6!/0!6!

6C6 = 1

Hence, the number of string with weight 6 is 1

7. Number of string with weight 7 is 0

Weight of 7 means that a string that has 7 occurrence of 1

The total length of a 6 bit is 6

Since 6 is less than 7, there's no way a bit of weight 7 can occur.

So, the right answer for this is 0.

8 0
3 years ago
A smoothie cafe has the ingredients needed to make 50,000 Smoothies on a day when the high temperature is expected to reach 90F.
DIA [1.3K]

Answer: my teacher did this with me today.

Step-by-step explanation:

Explanation in picture

4 0
2 years ago
Dan likes to go to the movies. He has budgeted $50 next month for the movie theater. It costs him $8.50 for a ticket each time h
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The Max amount of times he can go is 5 times
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