Answer:
h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))
Step-by-step explanation:
h(x) = ln x / √(x² + 1)
You can either use quotient rule, or you can rewrite using negative exponents and use product rule.
h(x) = (ln x) (x² + 1)^(-½)
h'(x) = (ln x) (-½) (x² + 1)^(-³/₂) (2x) + (1/x) (x² + 1)^(-½)
h'(x) = (-x ln x) (x² + 1)^(-³/₂) + (1/x) (x² + 1)^(-½)
h'(x) = (x² + 1)^(-³/₂) (-x ln x + (1/x) (x² + 1))
h'(x) = (1/x) (x² + 1)^(-³/₂) (-x² ln x + x² + 1)
h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))
For decimals, move the decimal point 2 units to the right to get the percentage.
0.125 = 12.5%
0.09 = 9%
for fractions, if it is over 100, make it the percentage of the number
so for 11 over 100, it is 11%
for example, 50 over 100, it is 50%
if it is not over one hundred, divide the numerator to denominator to get a decimal, and then make it into a percentage
for example 11/35. 11 divided by 35 is 0.31
0.31 = 31%
that is just an example
hope this helps
Answer:
BBBBB
Step-by-step explanation:
Answer:
first one is SAS
Step-by-step explanation:
Answer: x^2+5x+6
Step-by-step explanation:
