Answer:
<u>Given :</u>
length offshore = CS=√(1+X^2)
Cable charged = 5000√(1+X^2)
onshore length = 4-X
laying cost = 3000(4-X)
total cost:
C=5000√(1+X^2) +3000(4-X)
DC/DX
= [5000*(0.5)*2X/{√(1+X^2)}]-3000=0... for optimum
5000X=3000√(1+X^2)
25X^2=3+3X^2
22X^2=3
X=√(3/22)
= 0.3693 miles
So, it would be laid offshore to S in a manner that
BS=X=0.3693 miles
Onshore=4-0.3693
=3.6307 miles
Answer:
b
Step-by-step explanation:
you can use a calculator, or this way of thinking about it :
the sqrt of 49 is 7. so rt46 is too small, and rt51 may be too big. rt50 is closer to rt49 ( 7's square) than rt47. so it is rt50
If you want I can show you how to solve it
Answer:
I am led to believe the answers are 4 and 1
Step-by-step explanation:
I don't think its answer 2 because thou are radios and their isn't any fractions in it
I solved answer 4 it came as a fraction
Okay i looked at 1 and i did all of them they all came out as a decimal so i think that's another one
answer 3 you can't divide by 0 so i don't think so
The volume of the cone is 3.14 x 14 x 14
