Answer:
The range of heights of the cheerleaders is the interval [58, 74)
All real numbers greater than or equal to 58 inches and less than 74 inches
Step-by-step explanation:
we have
Divide the compound inequality into two inequalities
-----> inequality A
-----> inequality B
Solve inequality A
Subtract 28 both sides
Divide by 4 both sides
Rewrite
Solve the inequality B
Subtract 28 both sides
Divide by 4 both sides
therefore
The range of heights of the cheerleaders is the interval [58, 74)
All real numbers greater than or equal to 58 inches and less than 74 inches
Answer:
Step-by-step explanation:
You'll need to get this equation in slope-intercept form by solving for y. I do a little extra here to get it in the correct form, but I think it's pretty clear. Let me know if I need to clarify.
Once it's in slope-intercept form, both the slope and the y-intercept are readily available so you can easily graph it. I graphed both of them in the attached image so you can see that they are the same line.
Complete question is;
A 21 ft ladder is leaning against a tall wall with the foot of the ladder placed at 7 feet from the base of the wall and the angle of elevation is?
Answer:
θ = 70.5°
Step-by-step explanation:
The angle of elevation simply means the angle that the ladder makes with the ground. Let's call this angle θ.
I've attached a diagram showing the triangle made by this ladder and the wall.
From the attached diagram, we can see the triangle formed by the ladder and the wall.
We can find the angle of elevation θ from trigonometric ratios.
Thus;
7/21 = cos θ
cos θ = 0.3333
θ = cos^(-1) 0.3333
θ = 70.5°
That is approximately, in order, a C, a C, a B, a D, an A, a B, and an A.
In grade points that is a 2, a 2, a 3, a 1, a 4, a 3, and a 4.
The average of those numbers is about 2.7, so you have a 2.7.
You can raise that by bringing up the D as it is an outlier here.
381 1/10- 214 43/100= 166 67/100
