Answer:
The answer is -(29+3a).
Step-by-step explanation:
=2(3-4a)+5(a-7)
= 6- 8a +5a -35
= 6-35-8a+5a
= -29-3a
= -(29+3a)
<em>Hope</em><em> </em><em>it helps</em><em>.</em><em>.</em>
Answer:
95 city and 175 highway miles.
Step-by-step explanation:
The driver gets 20 mpg in city, and 28 mpg on the highway.
An equation that could be written is
20x+28y=270
This equation accounts for the distance traveled.
x+y=11
This equotion accounts for how many gallons were driven.
Multiply the bottom equation by 20, so you can solve the set of equations.
20x+28y=270
20x+20y=220
subtract them
8y=50
y=6.25
now plug this back into x+y=11
x+6.25=11
x=4.75
Now 4.75×20=95 city miles and 6.25×28=175 highway miles.
Answer:
a, the following expression equals 13
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher
The answer is 113.04 should be correct...