Xy + 6e^y = 6e
taking first derivative :
<span>xy' + y + 6y(e^y)(y') = 0 </span>
<span>xy" + y' + y' + 6y'(e^y)(y') + 6yy(e^y)y' + 6y(e^y)y" = 0 </span>
<span>Put x = 0,
0 + 6e^y = 6e,
y = 1 </span>
<span>0 + 1 + 6(1)(y')e = 0,
Put y' = 0 </span>
<span>0 + 0 + 0 + 0 + 0 +6 ey" = 0,
y" = 0</span>
Answer:
Given,
p (x)=2x-3
g (x)=6x+4
p (x)×g (x)=?
Step-by-step explanation:
p (x)×g (x)=(2x-3)(6x+4)
=2x (6x+4)-3 (6x+4)
=12x^2+8x-18x-12
=12x^2-10x-12
No, millie is not correct.
if one gallon = 8 pints, then
two gallons = 16 pints.
20x3 would 60
Just mutiply the number fishes with 3
