$\bf A(t)=942e^{-0.012t}\qquad \boxed{\stackrel{\textit{after 71 years}}{t=71}}\qquad \qquad A(t)=942e^{-0.012(71)}
\\\\\\
A(t)\approx 401.82042087707606813879$

4 0

3 years ago

Read 2 more answers

I suck at this please help... :,(

loris [4]

A quadrilateral with two pairs of sides

4 0

3 years ago

In this triangle, what is the value of x?

nalin [4]

Answer: $x=56.5\ km$

Step-by-step explanation:

Given the right triangle in the image, you need to remember the following identity:

$cos\alpha=\frac{adjacent}{hypotenuse}$

Observe the triangle. You can identify that:

$\alpha=28\°\\adjacent=x\\hypotenuse=64$

Then, knowing these values, you can substitute them into $cos\alpha=\frac{adjacent}{hypotenuse}$ :

$cos(28\°)=\frac{x}{64}$

Finally, you have to solve for "x".

Therefore, the value of "x" rounded to the nearest tenth is:

$64*cos(28\°)=x\\x=56.5\ km$

8 0

3 years ago

Write the amount shaded as a fraction.Then write the fraction as a decimal.

VladimirAG [237]

Answer:

Dude I am bad at fractions sorry. But I will do anything to get brainlyist. I want it. Look at my home page.

8 0

3 years ago