Answer:
<h3>The answer is option C</h3>
Step-by-step explanation:
6x³ - 4x² - 16x
To factorize the expression first factor out the GCF out
The GCF in the expression is 2x
That's
2x( 3x² - 2x - 8)
Next Factorize the terms in the bracket
To factorize write - 2x as a difference
that's
2x( 3x² + 4x - 6x - 8)
<u>Factor out x from the expression</u>
2x [ x( 3x + 4) - 6x - 8 ]
<u>Next factor out - 2 from the expression</u>
2x [ x ( 3x + 4) - 2( 3x + 4) ]
<u>Factor out 3x + 4 from the expression</u>
We have the final answer as
<h3>2x( 3x + 4)( x - 2)</h3>
Hope this helps you
Answers: 7x^2y^2 -3x+6y
I am not sure how to explain it but here you go
Answer:
EF = 58/7
Step-by-step explanation:
If you extend both BC and AD to meet at P you get 3 similar triangles PAB, PEF, and PCD. Let's call BF = 3x and FC = 4x. Therefore the following proportions can be expressed:
BP/7 = (BP+7x)/10
10BP = 7*(BP+7x)
10BP = 7BP+49x
3BP = 49x
BP = (49/3)x
BP/7 = (BP+3x)/EF
EF = (BP+3x)*7/BP
EF = ((49/3)x + 3x)*7/((49/3)x)
EF = ((58/3)x*7*3)/(49x)
EF = 58/7
The first one : -6
the second : -14
![\bf \begin{array}{llll} sin^{-1}[sin(whatever)]= whatever\\\\ cos^{-1}[cos(whatever)]= whatever\\\\ tan^{-1}[tan(whatever)]= whatever \end{array}\\\\ ------------------\\\\ \begin{array}{llll} sin[sin^{-1}(whatever)]= whatever\\\\ cos[cos^{-1}(whatever)]= whatever\\\\ tan[tan^{-1}(whatever)]= whatever \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%0Asin%5E%7B-1%7D%5Bsin%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Acos%5E%7B-1%7D%5Bcos%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Atan%5E%7B-1%7D%5Btan%28whatever%29%5D%3D%20whatever%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A------------------%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Asin%5Bsin%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Acos%5Bcos%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Atan%5Btan%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%0A%5Cend%7Barray%7D)
