You would have to multiply 25*1/6 and you would get your answer.
which is 4.167 which you would round to 4.
For example, if you are asked to estimate the sum of 545 + 723, you have to round the two numbers to the hundreds, so 545 would equal 500 and 723 would equal 700
500 + 700 = 1200, which wud be the estimation f the sum
Answer:
9 days
Step-by-step explanation:
Since the secret spread at a geometric rate we will use the geometric progression formulae
ar^n-1
First term = a= 5
common ratio is 2
For the nth term
5*2^n-1 = 1280 divide both sides of the equation with 5
2^n-1 = 256
2^n-1= 2^8
n-1 =8
n = 8+1
n=9
All the children will know the secret in 9 days
Alternatively
2nd day= 5*2^2-1
5*2^1=
5*2= 10
3rd day = 20
4th day= 40
5th day= 80
6th day = 160
7th day = 320
8th day =640
9th day =1280 children
Wait what segment? I don’t see any pictures.
y = 9ln(x)
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2
curvature k = |y''| / (1 + (y')^2)^(3/2)
<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2)
= (9/x^2) / (1 + 81/x^2)^(3/2)
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)]
= 9x(x^2 + 81)^(-3/2).
To maximize the curvature, </span>
we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2)
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2]
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2)
Setting k' = 0 yields x = ±9/√2.
Since k' < 0 for x < -9/√2 and k' > 0 for x >
-9/√2 (and less than 9/√2),
we have a minimum at x = -9/√2.
Since k' > 0 for x < 9/√2 (and greater than 9/√2) and
k' < 0 for x > 9/√2,
we have a maximum at x = 9/√2. </span>
x=9/√2=6.36
<span>y=9 ln(x)=9ln(6.36)=16.66</span>
the
answer is
(x,y)=(6.36,16.66)
