Answer:
Combine the terms
300 + 70 = 370
5/10 + 8/100
Note that first, you must find common denominators. What you multiply to the denominator, you multiply to the numerator. Multiply 10 to the numerator and denominator of 5/10
(5/10)(10/10) = 50/100
50/100 + 8/100
Combine the terms
50/100 + 8/100 = 58/100
370 58/100 is another way to write it
Answer:
A. right 2, up 3
Step-by-step explanation:
We have that,
The function
is transformed to
.
We see that,
The function f(x) is translated 2 units to the right and 3 units upwards to obtain the function g(x).
So, the correct transformation is 'right 2, up 3'.
Hence, option A is correct.
I believe the answer to your question is 11650
Answer:
21 matches
Step-by-step explanation:
This is a combination problem where we have to select two member out of 7 members
So we want calculation of 7C2
7C2 = 7!/[(2!)(7-2)!]
(7*6*5*4*3*2*1)/[(2*1) *(5*4*3*2*1]
(7*6)/2 ~ Note everything that easily cancels here!
42/2
21 matches
Answer:
35 different routes
Step-by-step explanation:
The problem of how many different routes are possible if a driver wants to make deliveries at 4 locations among 7 locations is a combination problem.
Combination problems are usually selection problems, of all or part of a set of options, without considering the order in which options are selected.
The number of combinations of n objects taken r at a time is: ⁿCᵣ
So, the number of ways the driver can make deliveries at 4 locations out of 7 locations of given by
⁷C₄ = 35 different ways.
Hence, 35 different routes are possible to make deliveries at 4 locations out of 7 locations.
Hope this Helps!!!