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Draw the diameter from point (-1, -5) to point (2, 3).
The triangle has base 3 and height 8.
The diameter of the semicircle is the hypotenuse of the triangle.
The radius is half the diameter.
The total area is the area of the triangle plus the area of the semicircle.
The triangle has base 3 and height 8.
The diameter of the semicircle is the hypotenuse of the triangle.
The radius is half the diameter.
The total area is the area of the triangle plus the area of the semicircle.
From a formula located here:
http://www.1728.org/quadltrl.htm
we see that
<span>4 • Side² = Long Diagonal² + Short Diagonal²
Long Diagonal = 24
Short Diagonal = 10
</span><span>4 • Side² = 24^2 + 10^2 </span>
<span>4 • Side² = 576 + 100
</span><span>4 • Side² = 676
</span><span><span>Side²</span> = 169
Side (or line AB) = 13
</span>
http://www.1728.org/quadltrl.htm
we see that
<span>4 • Side² = Long Diagonal² + Short Diagonal²
Long Diagonal = 24
Short Diagonal = 10
</span><span>4 • Side² = 24^2 + 10^2 </span>
<span>4 • Side² = 576 + 100
</span><span>4 • Side² = 676
</span><span><span>Side²</span> = 169
Side (or line AB) = 13
</span>