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3 years ago

In a triangle HIJ, i = 6.6 inches, j = 6.4 inches and Angle,H=62º. Find the length of h, to the

Mathematics

1 answer:

sweet [91]3 years ago

8 0

Answer:

7.6 inches

Step-by-step explanation:

We solve the above question using the Law of Cosines.

The formula is given as:

h² = i² + j² - 2ij Cos H

h = √i² + j² - 2ij Cos H

From the above question:

i = 6.6 inches

j = 6.4 inches

Length h = ?

Angle H=62º.

Hence:

h= √6.6² + 6.4² - 2 × 6.6 × 64 × Cos 62

h = √43.56 + 40.96 - 84.48 × Cos 62

h = 7.64292 inches

Approximately to the nearest tenth, Length h = 7.6 inches

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Solve this x²+8/10 -x = 10/2

AysviL [449]

$x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
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x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
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4 years ago

Please help me. I don’t know how to do this I really need this answer.

Ainat [17]

The answer is c.
I will explain

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1. Move variable to the right by adding it’s opposites on both sides

p - 2r + 2r = q + 2r

2. Eliminate the opposites (-2r and +2r)

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3 years ago

How can you solve for x and y?

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3 years ago

dolphi86 [110]

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In short, Your Answer would be 49 cm

Hope this helps!

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