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Zielflug [23.3K]
2 years ago
15

Find each measure. 25-29

Mathematics
1 answer:
hammer [34]2 years ago
8 0

       The only ones we can see in the question is 25, 27, and 29, but I have also included the other angles numbered as they are needed to solve some of the questions shown. I am not sure which problem number angel 1, 3, and 5 relate too though!

<u>Notes to know: </u>

- Triangle's angles add up to 180 degrees

- A box at an angle means it is equal to 90 degrees

1 = 62°

We have all we need to solve, 180 - 90 - 28 = 62°.

(see angle #2 for a more detailed explanation, I did them out of order haha)

25 aka 2 = 39°

The sum of a triangle's angles is 180°, in this triangle we can see a 51°, so 180° - 51° is 129°. We can also see it is next to a right triangle, so 129° - 90° = 39°. We can test this by adding them together. 39° + 51° + 90° = 180°, so this answer checks.

3 = 26°

A straight line is 180° degrees. We can see that the 51° degrees on the bottom there is on a line. 180° - 51° is 129°, so we have all we need to find #3! Using the same method of a triangle being 180° degrees, 180° - 129° - 25° = 26°. To check, 26° + 129° + 25° = 180°, so the answer checks :D

27 aka 4 = 55°

I am using the measurement from angle 6, which is 35°, to solve this one! 180° - 90° - 35° = 55°.

5 = 55°

Using the similar methods from above, 180° - 90° - 35° = 55°. To check, 55° + 35° + 90° = 180°, so this answer checks :))

29 aka 6 = 35°

We need the angle measurement from 5, which is 55°, to solve angle 6! 90° - 55° = 35°, so angle 6 is 35° degrees!

I hope this helps and all of them are correct, have a great day!

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lubasha [3.4K]

Answer:

Therefore the equation of the line through ( -2 , -7 ) and ( 5 , 7 ) is

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Step-by-step explanation:

Given:

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Let,

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point B( x₂ , y₂) ≡ ( 5 , 7 )

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Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula,

(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\

Or

Equation of a line passing through a points A( x₁ , y₁) and i having slope m is given by the formula,

(y - y_{1} )=m\times(x-x_{1}) \\

Substituting the given values in a above equation we get

(y-(-7))=2\times (x-(-2))\\ \\(y+7)=2(x+2)\\\\(y+7)=2x+4\\2x-y=3\\2x-y=3...............\textrm{which is the required equation of the line AB}

Therefore the equation of the line through ( -2 , -7 ) and ( 5 , 7 ) is

2x - y = 3

8 0
3 years ago
Let $f(x) = x^2 + 4x - 31$. for what value of $a$ is there exactly one real value of $x$ such that $f(x) = a$?
enot [183]

To solve for this, we need to find for the value of x when the 1st derivative of the equation is equal to zero (or at the extrema point).

So what we have to do first is to derive the given equation:

f (x) = x^2 + 4 x – 31

 

Taking the first derivative f’ (x):

f’ (x) = 2 x + 4

 

Setting f’ (x) = 0 and find for x:

2 x + 4 = 0

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Therefore the value of a is:

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a = (-2)^2 + 4 (-2) – 31

a = 4 – 8 – 31

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3 years ago
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Answer:

5x+17

Step-by-step explanation:

2(x+7) + 3(x+1)

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