X-1/2x-1/4x=75 what the answer of this equation?

Which point is collinear to the point (0,0)? A) (1,0) B) (3,2) C) (4,1) D) (1,3)

Sonbull [250]

Answer:

All of them are right

Step-by-step explanation:

Are you sure the question was that?

Collinear means that it lies on the same line

Now, from every 2 points passes a unique line

So(0,0) and (3,2) are in a line

(0,0) and (1,0) are in an other line and so on

8 0

3 years ago

What is 4(-2)+(-3)(-5)?

Svetlanka [38]

I say that the answer is 7 bc it’s -8+15

8 0

3 years ago

Read 2 more answers

Today is sunday. Tom starts to read a book with 490 pages today. Sundays he reads 25 pages and on all other days he reads 4 page

mrs_skeptik [129]

Based on the information given, it can be noted that Tom will use 117 days to read the book.

How to solve a equation.

Based on the information given, we are informed that Tom starts to read a book with 490 pages today. Sundays he reads 25 pages and on all other days he reads 4 pages.

Let the number of days be represented by x. Therefore, the equation to solve the question will be:

25 + (4 × x) = 490

25 + 4x = 490

4x = 490 - 25

4x = 465

x = 465/4

x = 116.25

x = 117

Therefore, he'll use 117 days to read the book.

Learn more about equations on:

brainly.com/question/13763238

6 0

2 years ago

Evaluate the expression below at x = 5. x/35 + 5x^2

kramer

Answer:

876/7

Step-by-step explanation:

Just plug the number 5 into the equation and solve. Remember your Order of Operations (PEMDAS).

4 0

2 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago