Ask question

Ask question

All categories

4 years ago

15

X-1/2x-1/4x=75 what the answer of this equation?

1 answer:

vekshin14 years ago

5 0

Answer:

The answer and solution is above

You might be interested in

What is the 5-digit code?

kvv77 [185]

9514 1404 393

Answer:

4 2 6 1 7 or 1 2 4 3 7

Step-by-step explanation:

4 are correct of 1,3,4,6,7

3 are correct of 0,2,3,6,7

1 is correct of 0,3,6,8,7 -- so not both 3 and 6, meaning 1, 4, 7 are correct

Correct digits so far are 1, 4, 7 and one of {3, 6}. Line 2 tells another is 0 or 2; line 3 tells it is not 0. This adds 2 to the list of correct digits.

This makes the correct digits 1, 2, {3, 6}, 4, 7. We don't know whether the last digit is 3 or 6.

__

Looking at digits correctly placed, line 2 tells us the code is either ...

_ 2 6 _ 7 or _ 2 _ 3 7

Then line 1 fills in those blanks as ...

4 2 6 1 7 or 1 2 4 3 7

Either of these codes agrees with all of the clues.

3 0

3 years ago

Find the missing lengths: LK=15 and KH=9, find KI and HI.

Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

$base^2+perpendicular^2=hypotenuse^2$

Use Pythagoras in triangle HKL

$LH^2+KH^2=LK^2$

$(LH)^2+9^2=15^2$

$(LH)^2+81=225$

$(LH)^2=144$

Taking square root on both sides.

$LH=12$

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

$(KI)^2+15^2=(12+x)^2$

$(KI)^2+225=x^2+24x+144$

$(KI)^2=x^2+24x+144-225$

$(KI)^2=x^2+24x-81...(1)$

Use Pythagoras theorem in ΔHKI,

$(KI)^2=x^2+9^2$

$(KI)^2=x^2+81...(2)$

From (1) and (2) we get

$x^2+81=x^2+24x-81$

$24x=162$

$x=\dfrac{162}{24}=6.75$

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

$(KI)^2=(6.75)^2+81$

$(KI)^2=126.5625$

Taking square root on both sides.

$KI=\sqrt{126.5625}$

$KI=11.25$

Hence, the measure of KI is 11.25 units.

3 0

3 years ago

Which is larger 4 yards or 13 feet?

Dmitrij [34]

13feet is larger as 4 yard is equivalent to 12 feet

8 0

3 years ago

Read 2 more answers

Please help, it's urgent!

Aneli [31]

For this case we have to, by defining properties of powers and roots the following is fulfilled:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$

We must rewrite the following expression:

$\sqrt [3] {8 ^ {\frac {1} {4} x}}$

Applying the property listed we have:

$\sqrt [3] {8 ^ {\frac {1} {4} x}} = 8 ^ {\frac{\frac {1} {4} x} {3} }= 8 ^ {\frac {1} {4 * 3} x} = 8 ^ {\frac {1} {12} x}$

Using the property again we have to:

$8 ^ {\frac {1} {12} x} = \sqrt [12] {8 ^ x}$

Thus, the correct option is option C

Answer:

Option C

6 0

3 years ago

Read 2 more answers

How do I solve cos x> 1/2 sin x?

Hatshy [7]

Divide both sides by $\dfrac12\cos x$ :

$\dfrac{\cos x}{\frac12\cos x}>\dfrac{\frac12\sin x}{\frac12\cos x}\implies2>\dfrac{\sin x}{\cos x}=\tan x$

If $-\dfrac\pi2$ , then

$\tan x$

and more generally, for any integer $n$ ,

$n\pi-\dfrac\pi2$

4 0

3 years ago