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3 years ago

The expression 1/2 bh gives the area of a triangle where

Mathematics

1 answer:

mixer [17]3 years ago

8 0

Answer:

yes that's correct

Step-by-step explanation:

let's say a question was given with the base of a triangle as 5cm and the height triangle as 8cm.

you will go by

<em><u>solution</u></em>

area = 1/2 * b * h

area = 1/2 (5 * 8)

area = 1/2 (40)

area = 20cm²

hope this helps

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Solve each problem and check your answer using estimates. a. $18.79 + $2.11 + ‐$1.92 + $17.28 b. $7.45 + ‐$24.45 + $74.17 + ‐$76

Aneli [31]

The solution to the linear expressions are:

a. $36.26
b. -$19.35
c. $70.38

<h3>Solving linear expressions:</h3>

The solution to linear expression is determined by taking into consideration the arithmetic operations used in each linear expression.

From the information given:

a. $18.79 + $2.11 + ‐$1.92 + $17.28

By rearrangement:

= $18.79 + $2.11 + $17.28 ‐$1.92

= $36.26

b. $7.45 + ‐$24.45 + $74.17 + ‐$76.52

By rearrangement:

= $7.45 + $74.17 ‐ $24.45 ‐ $76.52

= -$19.35

c. $98.45 − $10.63 + $2.82 − $20.26

By rearrangement:

= $98.45 + $2.82 − $10.63 − $20.26

= $70.38

Learn more about solving linear expressions here:

brainly.com/question/2030026

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7 0

2 years ago

Lloyd was paid a 6% commission on sales of $95,292. How much money was he paid in commissions?

alexgriva [62]

$5717.52

You’d just take the 6 percent and make it 0.06 then multiply it by 95,292

4 0

3 years ago

A.d2=4 is true for<br><br>b.2m=m+m is true for<br><br>c. d+67=d+68 is true for

Rufina [12.5K]

A. 2(2) = 4
B. 2(1)= 1+1
C. 2+ 67 = 1+ 68

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3 years ago

The computer center at Dong-A University has been experiencing computer down time. Let us assume that the trials of an associate

Schach [20]

Answer:

(a)0.16

(b)0.588

Step-by-step explanation:

The matrix below shows the transition probabilities of the state of the system.

$\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix $P^k$ .

(a)

$P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

$P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}$

If the system is initially running, the probability of the system being down in the next hour of operation is the $(a_{12})th$ entry of the P^2$ matrix.$

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

$P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}$

Therefore, the probability that a system initially in the down-state is running

is 0.588.

(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, $S=[s_1$ s_2]$

$[s_1$ s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$ s_2]$

Using a calculator to raise matrix P to large numbers, we find that the value of $P^k$ approaches [0.75 0.25]:

Furthermore,

$[0.75$ 0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$ 0.25]$

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

$[s_1$ s_2]=[0.75$ 0.25]$

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4 years ago

Write 5600000 in standard form

umka2103 [35]

Answer:-5600000

Step-by-step explanation:

4 0

3 years ago