All categories

3 years ago

Which of these pairs of variables would you expect to be represented by a scatterplot with a positive correlation?

2 answers:

meriva3 years ago

6 0

The answer would be B because the depth of the water would change depending upon the amount of rainfall, and this would create different depths which would be displayed throughout the scatter plot.

qwelly [4]3 years ago

3 0

B would be your answer

You might be interested in

An apartment complex has a floor plan with dimensions shown. To effectively air condition a room, 20 BTU’s are required for ever

kifflom [539]

12,900 BTU's are required to cool the room effectively.

Step-by-step explanation:

Step 1:

We must calculate the area of the entire shape to determine the minimum BTU's required to cool the room effectively.

It is made up of a semi-circle a rectangle, and a trapezoid.

Step 2:

The area of a semi-circle $=\frac{ \pi r^{2} }{2} .$

Here, the diameter is 20 feet so the radius is 10 feet.

The area of the semi-circle $=\frac{ \pi r^{2} }{2} =\frac{ (\pi) (10^{2}) }{2} = 157.079$ square feet.

The area of a rectangle $= (l)(w).$

The length of the rectangle is 22 feet and the width is 20 feet.

The area of a rectangle $= (l)(w) =(22)(20) = 440$ square feet.

The area of a trapezoid $=\frac{a+b}{2} (h).$

Here $a=12, b= 20, h= 3$ .

The area of a trapezoid $=\frac{12+20}{2} (3) = 48$ square feet.

Step 3:

The total area of the floor plan $=157.079+440+48 = 645.079$ square feet.

If 20 BTU's are required for a single square foot,

The number of BTU's for 645.079 square feet $= (645.079)(20)=12,901.58$ BTU's.

Rounding this off, we get 12,900 BTU's required to cool the room effectively.

7 0

3 years ago

What is 6574893 + 7?????

Effectus [21]

Answer:

6574900

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Write an expression for "the quotient of 9 and c

Natalka [10]

Answer:

9/c or c/9

Step-by-step explanation:

3 0

3 years ago

Graph the systems of equations.<br><br> {2x+y=8−x+2y=6

victus00 [196]

Hi, I actually just took the test and got 100%

Remember: When plotting the points for this equation, make sure to always first plot the ones that correspond to the first linear equation, and then plot the ones that correspond to the second linear equation.

The points on the line should be for the first linear equation, (4,0) and (8,0). I got this answer by first converting the linear equation, 2x+y=8 from standard form to slope-intercept form. To do this, I subtracted 2x from both sides of the equation. So now it reads as y=8-2x. After this step was completed, I then graphed my first linear equation.
The points on the line should be for the first linear equation, (2,4) and (6,6).
I got this answer by first converting the linear equation, -x+2y=6 into slope-intercept form. To do this, I subtracted -x from both sides of the equation. Then I had to divide the 2 into both -x and 6. So now it reads as y= 6/2-x/2. After this step was completed, I then graphed my second and final linear equation.

I hope this helps!

5 0

3 years ago

Read 2 more answers

The combined (verbal + quantitative reasoning) score on the GRE (Graduate Record Exam) is normally distributed with mean 1049 an

mash [69]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Normal distribution :

Mean (m) = 1049

Standard deviation (sd) = 189

Number of samples (n) = 16

A) What is the probability that one randomly selected student scores above 1100 on the GRE?

Obtain the z score

Zscore = (x - m) / sd

Zscore = (1100 - 1049) / 189

Zscore = 51 / 189 = 0.2698412 = 0.27

Using the z-table

P(X > 100) = 1 - P(X < 100) = 1 - 0.6064 = 0.3936

B) The sample mean = population mean

Hence sample mean = 1049

The sample standard deviation = standard error

Standard Error (SE) = sd / sqrt(n)

SE = 189/4 = 47.25

Hence shape = normal, standard deviation = 47.25, mean = 1049

C.) P(X < 1100)

Zscore = (x - m) / SE

Zscore = (1100 - 1049) / 47.25

Zscore = 51 / 47.25 = 1.0793650 = 1.08

Using the z-table :

P(X < 1100) = 0.8599

D.) P(X > 1100)

Zscore = (x - m) / SE

Zscore = (1100 - 1049) / 47.25

Zscore = 51 / 47.25 = 1.0793650 = 1.08

Using the z-table :

P(X > 1100) = 1 - P(X < 1100) = (1 - 0.8599) = 0.1401

E) if n = 64

SE = 189 / sqrt(64) = 189 / 8 = 23.625

P(X > 1100)

Zscore = (x - m) / SE

Zscore = (1100 - 1049) / 23.625

Zscore = 51 / 47.25 = 2.1587301 = 2.16

Using the z-table :

P(X > 1100) = 1 - P(X < 1100) = (1 - 0.9846) = 0.0154

The probability decreases as the same distribution hinges towards a Boal distribution with increasing sample size.

3 0

3 years ago