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Liula [17]
3 years ago
15

A reason improper use of netiquette can be risky is that users can

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
5 0
A


Mark brainliest please


Hope this helps you
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Marcos finished 75% of his homework. If he had 20 pages of homework, how many pages did he complete?
Nookie1986 [14]
We know that

<span>20 pages of homework correspond to ---------------> 100%
 x pages -------------------------------> 75%
x=75%*20/100%-----> 15 pages

the answer is
15 pages</span>
6 0
4 years ago
How many solutions does y=3/4 x + 12 y= 4/3 x have
Licemer1 [7]

Answer:

all you have to do is use Desmos graphing calculators and there you go you will thank me later

4 0
3 years ago
Factor the polynomial function over the complex numbers?? <br><br><br><br> F(x)= x^4 -x^3-2x-4
pav-90 [236]

Answer: The factor form of the function F(x) is (x+1)(x-2)(x^2+2), where  (x^2+2) gives two complex roots.

Explanation:

The given function is,

F(x)=x^4-x^3-2x-4

According to the rational root theorem 1 and -1 are the possible roots of each polynomial.

Put x=-1

F(-1)=(-1)^4-(-1)^3-2(-1)-4=0

Since the value of F(x) is 0 at x=-1 therefore the -1 is a root of given polynomial and (x+1) is a factor of F(x).

Use synthetic division method to divide the polynomial by (x+1).

The last row of the synthetic division shows the coefficient of remaining polynomial.

F(x)=x^4-x^3-2x-4=(x+1)(x^3-2x^2+2x-4)

At x=2 the value of F(x) is 0, therefore (x-2) is a factor of F(x).

Use synthetic division method to divide the polynomial by (x-2).

F(x)=(x+1)(x-2)(x^2+2)

Therefore the roots of F(x) are,

-1,2,\pm i\sqrt{2}

F(x)=(x+1)(x-2)(x+i\sqrt{2})(x-i \sqrt{2} )

Where (x+1)(x-2) factors with real root and (x+i\sqrt{2})(x-i \sqrt{2} ) are factors with complex roots.

8 0
3 years ago
Can anyone solve the system using the elimination method (TIMED)<br> 3x-5y=7<br> 2x-3y=6
steposvetlana [31]

Answer:

Hopefully help

Step-by-step explanation:

the answer in the picture

8 0
3 years ago
Can someone help me out
Svetradugi [14.3K]
The answer is g4 -2 hope this helps
6 0
4 years ago
Read 2 more answers
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