Question

Find the missing measure indicated in the given triangle.

Answer 1

Answer:

17.75°

Step-by-step explanation:

Since it is a right triangle, we can use pythagorean theorem to find the unknown side, side opposite of the angle "?".

Let that side be "x", so we can write (using pythagorean theorem):

$x^2+20^2=21^2$

Now, solving for x:

$x^2+20^2=21^2\\x^2+400=441\\x^2=41\\x=\sqrt{41}$

Now we use Law of Cosines to solve for the angle "?".

Law of Cosines:  $p^2=a^2+b^2-2abCosP$

Where

p is the side opposite to angle

P is the angle (we want to solve for)

a, and b are the two sides given

Thus, we have:

$p^2=a^2+b^2-2abCosP\\(\sqrt{41})^2=21^2+20^2-2(21)(20)CosP\\41=841-840CosP\\840CosP=800\\CosP=0.9524\\P=Cos^{-1}(0.9524)\\P=17.75$