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lisabon 2012 [21]
3 years ago
10

Help! I do not understand a single thing lol I’m sorry<3

Mathematics
2 answers:
Sholpan [36]3 years ago
8 0

<h3>{4c}^{2} d {}^{2}  - 8c {}^{4} d + 16c - 2d \\ the \: value \: of \: c =  - 1 \\ the \: value \: of \: d \:  = 4 \\ 4 \times  {( - 1)}^{2}  \times  {4}^{2}  - 8 \times  {( - 1)}^{4}  \times 4 + 16 \times ( - 1) - 2 \times 4 \\ 4 \times 16 - 8 \times 4 - 16 - 8 \\ 64 - 32 - 16 - 8 \\ 8</h3>

Sorry if I am incorrect.....

kati45 [8]3 years ago
4 0

=<em> </em><em>8</em><em> </em>

<em>step-by-step</em><em> </em><em>explanation:</em>

<em>evaluate</em><em> </em>

<em>-8c⁴</em><em> </em><em>d </em><em>+</em><em>4</em><em>c</em><em>²</em><em> </em><em>d²</em><em> </em><em>+</em><em> </em><em>1</em><em>6</em><em>c</em><em> </em><em>-</em><em> </em><em>2</em><em>d</em>

<h2 />

<em>when </em><em>c </em><em>=</em><em>-</em><em>1</em><em> </em><em>,</em><em>d=</em><em>4</em>

<em>=</em><em>8</em>

<h2><em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>!</u></em></h2>

<em><u>#</u></em><em><u>c</u></em><em><u>a</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>on</u></em><em><u> learning</u></em>

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Write the equation of the circle whose center is (-4,8) and has a diameter of 18
svetoff [14.1K]

Answer:

(x + 4)^2 + (y - 8)^2 = 81

or

(x + 4)^2 + (y - 8)^2 = 9^2 depending on how your teacher wants it written.

Step-by-step explanation:

The standard form for a circle is

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You are given the diameter

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So you already have the right hand side of the equation

(x + h)^2 + (y + k)^2 = 9*2

(x + h)^2 + (y + k)^2 = 81

You basically have h and k as well. They come from the center point.

h = 4

k = - 8

So the equation of the circle (and the answer) is

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One question remains. Why do the x and y values change signs? If you know what the distance formula is, then what you are finding is the distance r of all points on the circle from the center of the circle.

It is the distance formula that is actually the formula for the circle.

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3 years ago
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