Could you take another photo with you zoomed a lil bit more so I can answer it?
Answer: The expression that represents Meg's finishing time in June is "y - 10".
The problem started with Meg running in April. She had a time in April and we called it "y".
Now, Meg ran again in June. In June, she did 10 seconds faster. So it makes since that we need to subtract 10 from her April time, "y". Therefore, the expression is simply "y - 10".
Answer:
15°.
Step-by-step explanation:
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Have a good Day!
Answer:
194
Step-by-step explanation:
t63 = t1 + (n - 1)(d)
= 8 + (63 - 1)(3)
= 8 + (62)(3)
= 8 + 186
= 194
3√24= 3√2^2*6 = 3*2√6 = 6√6
2√384= 2√8^2*6 = 2*8√6 = 16√6
√96= √4^2*6 = 4√6
6√6 -16√6- 4√6 = -14√6
Final answer: -14√6