Answer:
I created a jsfiddle for this: https://jsfiddle.net/tonb/o7uv4cdm/26/
Explanation:
see jsfiddle.
The usual html and body tags are omitted for simplicity. For your stand-alone page you'll have to put them in, as well as additional tags for your inline scripting.
Answer:
Program :
list_1=[]#take the empty list.
size=int(input("Enter the size of the list: "))#take the size of the list from the user
for x in range(size): #for loop which insert the elemnt on the list.
list_1.append(int(input("Enter the "+str(x+1)+" element of the list: ")))#take the user input and insert the element.
element=int(input("Enter the element to be searched: "))#it take the elemnt to search.
loc=1#intialize the location value.
count=0
for x in list_1:#for loop to check the element.
if(x==element): #check the element.
print(loc,end=", ")#print the location of the element.
count=count+1
loc=loc+1
if(count==0):
print("The element is not present on the list")#print when elemnt are not present.
Output:
- If the user input 5 for the size and 1,2,3,4,5 for the list and 5 for the element, then it will print 5.
Explanation:
- The above code is in python language which is used to take the size for the list, then take the value to add on the list.
- Then the element is entered from the user to search on the list.
- Then the element is searched on the list with the help of for loop.
- It prints the location when the element is matched.
Answer:
TRUE, The PC is always incremented by the same amount in fixed-length instruction set architectures.
Explanation:
Its TRUE that Program Counter ( PC ) is always incremented by the same amount in fixed - length instruction set architectures ( fixed length ISA) . As the instruction set length is fixed in fixed - length instruction set architectures, the Program Counter to fetch the next instruction set it has to be incremented by fixed length. This fixed length depends on the hardware of the architecture (the number of bytes each machine word contains and number of machine words per memory location)
