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AlexFokin [52]
2 years ago
7

A computer hacker trying different combinations of characters to crack a password is a ________.

Computers and Technology
1 answer:
WITCHER [35]2 years ago
5 0

Answer:

Brute-force attack

Please Mark Brainliest If This Helped!

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import java.io\.\*; import java.nio.file\.\*; public class TestFileReader { public static void main(String[] args) { Path p = Pa
Charra [1.4K]

Answer:

The delimiter use is "::".

Explanation:

The Java inbuilt String.split( ) function is use to split a String into an array of String.

The split( ) takes delimiter as arguments/parameter which determines at which point the string is to be broken down into different part/token.

From the above code snippet;

Each line in the file a.txt that is not null is splitted using the statement below:

String[ ] v = line.split("::");

The line is splitted using "::" as delimiter and the resulting array is then assigned to the variable 'v'.

For instance, a line in the file could take the form:

John::Smith::Music

When it is splitted,

String lname = John;

because lname make reference to index 0 of the array.

String fname = Smith;

because fname make reference to index 1 of the array.

String dept = Music;

and dept make reference to index 2 of the array.

6 0
3 years ago
. An access specifier is one of three keywords:
Zolol [24]

Answer:

Access specifiers are used to control the visibility of members like classes, variables and methods. There are three access specifiers: public, private and protected. We shall see only about the public and private access specifiers for now. Protected access specifier comes into picture when inheritance is implemented. plz brainly me

Explanation:

8 0
3 years ago
In c++ 11, the ________ tells the compiler to determine the variable's data type from the initialization value.
sergiy2304 [10]
<span>In describing an Initialization is when a value is assigned to a variable as part of the variable's definition or the assinged values to variables are defined whenever. 

The best answer would be is that they present the keyword,  when they tell the compiler.</span>
3 0
4 years ago
Write a function called st_dev. st_dev should have one
aleksandrvk [35]
Huluttttttt!!! greggyffh
8 0
2 years ago
Given integer variables totalTickets, vipTickets, and sessionNum, which line of code correctly calls the following function? voi
alekssr [168]

Given integer variables <em>'totalTickets, vipTickets, and sessionNum'</em>, the line of code given in option C correctly calls the following function: "<em>void FinalTally(int* totalAttendees, int* vipAttendees, int numSessions);</em>"

The correct function call with the variables named <em>'totalTickets, vipTickets, and sessionNum</em>' is as follows:

<em>FinalTally(&totalTickets, &vipTickets, sessionNum); </em>

A function call refers to an expression that passes control and arguments (if there are any) to the specified function and has the syntax as <em>FunctionName (argumentList</em>) where <em>FunctionName is the name of the function to be called and argumentList indicates the list of arguments (separated by commas) to be passed to the calling function</em>.

"

<u><em>Correct question is as follows:</em></u>

Given integer variables totalTickets, vipTickets, and sessionNum, which line of code correctly calls the following function? void FinalTally(int* totalAttendees, int* vipAttendees, int numSessions);

a. FinalTally(totalTickets, vipTickets, &amp;session Num);

b. FinalTally(&amp;totalTickets, &amp;vipTickets, session Num);

c. FinalTally(&totalTickets, &vipTickets, sessionNum);

d. FinalTally(&amp;totalTickets, &amp;vipTickets, &amp;session Num);

"

You can leran more about Function Call at

brainly.com/question/28566783

#SPJ4

3 0
1 year ago
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