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Firdavs [7]
3 years ago
11

Which set of numbers can represent the side lengths, in inches, of an acute triangle? 4, 5, 7 5, 7, 8 6, 7, 10 7, 9, 12

Mathematics
2 answers:
yarga [219]3 years ago
4 0

Answer:

4 5 7

Step-by-step explanation:

i know it

Natalija [7]3 years ago
3 0

Answer:

Set B i.e., 5 , 7 , 8 represent the side of acute angled triangle.

Step-by-step explanation:

Given: Set of numbers.

To find: Set that represent sides of an acute angled traingle.

We use the following result:

When given 3 triangle sides then to determine if the triangle is acute angled , right angled or obtuse angled.

First find Square all 3 sides, then Sum the squares of the 2 shortest sides and then Compare the sum to the square of the last side.

if sum > Square of last side ⇒ it is Acute Triangle

if sum = Square of last side ⇒ it is Right Triangle

if sum < Square of last side ⇒ it is Obtuse Triangle  

a). 4  , 5 , 7

4² = 16 ,  5² = 25 , 7² = 49

16 + 25 = 41

∵ 41 < 49

⇒ It is an Obtuse Traingle.

b). 5 , 7 , 8

5² = 25 , 7² = 49 , 8² = 64

25 + 49 = 74

∵ 74 > 64

⇒ It is an acute Triangle.

c). 6 , 7 , 10

6² = 36 , 7² = 49 , 10² = 100

36 + 49 = 85

∵ 85 < 100

⇒ It is an Obtuse Triangle.

d). 7 , 9 , 12

7² = 49 , 9² = 81 , 12² = 144

49 + 81 = 130

∵ 130 < 144

⇒ It is an Obtuse Triangle.

Therefore, Set B i.e., 5 , 7 , 8 represent the side of acute angled triangle.

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Step-by-step explanation:

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(2x +1) -7 (-6x+9) what is the answer if using the Distributive Property?
Margarita [4]

Answer:

Step-by-step explanation:

Distributive property:  a(b +c) = a*b + a*c

(2x + 1) - 7(-6x + 9) = (2x + 1) + (-7)*(-6x) + (-7)*9

                              = 2x + 1 + 42x - 63  {Combine like terms}

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A group consists of 6 men and 5 women. Five people are selected to attend a conference. In how many ways can 5 people be selecte
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Answer:

462

6

1.2%

Step-by-step explanation:

Since the questions are combinations, we must apply the combination formula, which is as follows:

n C r = (n!) / (r! (n-r)!)

Because there are 6 men and 5 women, there are a total of 11 people.

Thus:

n = 11

In the first question in how many ways can 5 people be selected from this group of 11, r = 5.

Replacing in the formula:

11 C 5 = (11!) / (5! * (11-5)!)

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11 C 5 = 462

In the second question, in how many ways can 5 men be selected from the 6 men, here n = 6 and r = 5, replacing we are left with:

6 C 5 = (6!) / (5! * (6-5)!)

6 C 5 = (6!) / (5! * 1!)

6 C 5 = 6

In the last question of what is the probability that the selected group is all men, we have that it is the combination of the two previous questions. Since the total would be part A it would be the total of the combinations of choosing 5 of 11 people and part B of the 6 men that there are the combinations of choosing 5.

Divide the two values ​​from parts A and B to get ...

(result from part B) / (result from part A) = (# of ways to pick 5 men) / (# of ways to pick 5 people)

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In other words, the probability is 1.2%

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