Answer: I'm not sure if this is right or not but I got U = 4
Step-by-step explanation: -8(2v-2)=-4(7+5u. So first I distributed and got -16v -16 = 28 + 20u. And then I added 16u with 20u I added because you change the sign like if it's a negative you make it a positive so once you do 20u+16v you should get 36 and then on the other side it should be -16+16 which equals -16u from when you distributed so now you should have -16u=28+36 so now you would add 28 the 36 since they both are positives and have no variables which you should get 64 and then on the left you should have 16u. So it looks like -16u=64. And then now you would divide -16u on both sides and the side with the variable put it or v whatever variable you want to use and then do 64 divided by 16 and you should get 4.
(jk)(x)= j (k(x)) = j(9-2x)
= -7(9-2x) = -63 + 14x
but i see there is no such option. may be second option is typo.
so you can select 2nd option
Answer:
-1/5
Step-by-step explanation:
3/5 is greater than 2/5, so your answer goes into the negatives
Answer:
Is this in Pearson Easybridge?
Step-by-step explanation:
