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iren2701 [21]
3 years ago
11

Which equation is perpendicular to y-3=4(x+5) and passes through 4,-3)?

Mathematics
2 answers:
stich3 [128]3 years ago
5 0

Answer:

A

Step-by-step explanation:

y - 3 = 4(x+5)

Let's convert the point-slope equation to y-intercept form: y = mx + b

Distribute the 4 to the equation inside the parenthesis

y - 3 = 4x + 20

Add 3 to both sides

y - 3 = 4x + 20

 + 3         + 3

y = 4x + 23

The slope of this equation is 4, meaning our equation's slope will have to be -1/4 to be perpendicular

y = -1/4x + b

Plug in the given x and y

-3 = -1/4(4) + b

-3 = -1 + b

Add 1 to both sides

-3 = -1 + b

+ 1   + 1

b = -2

y = -1/4x - 2

kow [346]3 years ago
4 0

Step-by-step explanation:

....................

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Step-by-step explanation:

2 steps:

Step 1

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Step 2

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<h2>Naja earns 64$ per 8 hours of work</h2>
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3 years ago
Anyone know how to do this?
Reika [66]

Answer:

-2x-y-15

Step-by-step explanation:

5x+3y+4-9x-8+2x-4y-11

you add the x together

5x+2x=7x

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then yourewrite the problem

-2x+3y+4-8-4y-11

then you can solve for the y

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we can rewrite the problem again

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answer

-2x-y-15

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