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sdas [7]
2 years ago
7

A theme park has a Ferris wheel that takes 2 minutes to go around its 450-foot circumference. The equation · (130) = 450 relates

the speed of the Ferris wheel to its circumference. What exactly does represent?
Mathematics
1 answer:
olchik [2.2K]2 years ago
3 0

Answer: The Ferris wheel’s speed in feet per hour.

Step-by-step explanation:

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Please Explain How to Solve.
Shtirlitz [24]

Answer:

0.66653334

Step-by-step explanation:

The area of the face of the square is the side length x the side length. So 0.3333 x 0.3333 = 0.11108889. Since a square has 6 sides, multiply 0.11108889 with 6. So it equals 0.66653334.

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What is an equation of the line that passes through (-2,3) and (6,-1) ?
Marina CMI [18]

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2,7

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7 0
3 years ago
How does teh value of (18-12) divided by l2 compare to the value of 18-12?!?!?
Lerok [7]

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C is correct :)

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8/9 to what power equals 64/81
Ierofanga [76]

2nd

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8/9 to the second power equals to 64/81. Hope this helps!

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3 years ago
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A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
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