Question

What is the range of y= sec-'(x)? PreCal, send help please!!

Answer 1

Given:

The function is:

$y=\sec^{-1}(x)$

To find:

The range of the given function.

Solution:

We have,

$y=\sec^{-1}(x)$

The range of secant inverse function is:

$Range=\{y|0\leq y\leq \pi , y\neq \dfrac{\pi}{2}\}$

The range of the given function in interval notation is:

$Range=\left[0,\dfrac{\pi}{2}\right)\text{ and }\left( \dfrac{\pi}{2}, \pi\right ]$

Therefore, the correct option is C.