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Inessa05 [86]
3 years ago
5

What is the range of y= sec-'(x)? PreCal, send help please!!

Mathematics
1 answer:
beks73 [17]3 years ago
6 0

Given:

The function is:

y=\sec^{-1}(x)

To find:

The range of the given function.

Solution:

We have,

y=\sec^{-1}(x)

The range of secant inverse function is:

Range=\{y|0\leq y\leq \pi , y\neq \dfrac{\pi}{2}\}

The range of the given function in interval notation is:

Range=\left[0,\dfrac{\pi}{2}\right)\text{ and }\left( \dfrac{\pi}{2}, \pi\right ]

Therefore, the correct option is C.

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