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RUDIKE [14]
3 years ago
9

Find the value of x. NO LINKS AT ALL!! ​

Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0

Answer:

?

Step-by-step explanation:

lyudmila [28]3 years ago
5 0

Answer:

x= -7

The whole thing is just an awkward mirror but the lower triangle has an angle that is 1 degree smaller so the whole lower section is going to be bigger or smaller and the angle that mirrors the 80 degree angle is now 79 degrees which makes the other angle on that line 1 degree bigger which would be 101 so you put it in the expession to make it the equation -12x+17=101 and you solve for x which you would then get -7.

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Find the value of x and the unknown angle in each problem
Gnom [1K]
Hello!

Angle POQ and angle MON are vertical which means they are congruent

x - 28 = 149

Add 28 to both sides

x = 177

Angle NOQ and angle NOM are supplementary meaning they add to 180

NOQ + NOM = 180

Put in the known angle

NOQ + 149 = 180

Subtract 149 from both sides

NOQ = 31

The answers are x = 177 and angle NOQ = 31

Hope this helps!
4 0
3 years ago
-8=2/5t solve for t please!
Natali [406]
Your answer here is t = -20

-8 = 2/5t
Equation

2/5 = 0.4
2 divided by 5 is 0.4

-8 / 0.4 = -20
Divide -8 by 0.4 which is -20
5 0
3 years ago
Someone please help me on this math problem!
Galina-37 [17]

Look at the picture.

Therefore we have the equation:

10y - 29 = 7y + 19       <em>add 29 to both sides</em>

10y = 7y + 48          <em>subtract 7y from both sides</em>

3y = 48      <em>divide both sides by 3</em>

y = 16



3x + 7 = 5x - 21            <em>subtract 7 from both sides</em>

3x = 5x = -28         <em>subtract 5x from both sides</em>

-2x = -28     <em>divide both sides by (-2)</em>

x = 14

3 0
3 years ago
Solve the system using substitution x+5y=0 3y+2x=-21
Crazy boy [7]

Answer:

\left \{ {{x = -15} \atop {y=3}} \right.

Step-by-step explanation:

\left \{ {{x + 5y = 0} (1) \atop {3y + 2x = -21}(2)} \right.  \left \{ {{x = -5y} \atop {3y + 2x = -21}} \right.    \left \{ {{x = -5y} \atop {3y + 2*(-5y) = -21}} \right.  \left \{ {{x = -5y} \atop {3y - 10y = -21}} \right. \\ \left \{ {{x = -5y } \atop {-7y = -21}} \right.  \left \{ {{x = -5y} \atop {y= 3 }} \right.  \left \{ {{x = -5 * 3} \atop {y=3}} \right.=> \left \{ {{x=-15} \atop {y=3}} \right.

5 0
3 years ago
Read 2 more answers
Can somebody help me out?
Viefleur [7K]

Answer:

Yeah

Step-by-step explanation:

5 0
3 years ago
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