PLsssss hurrry Ineed help!! u will get alot of points wihthe correct answer

How many days will it take for a sum of $4,000 to earn $80 interest if it is deposited in a bank paying ordinary simple interest

Maksim231197 [3]

Answer:

It will take 146 days to earn an interest of $80.

Step-by-step explanation:

The simple interest formula is:

$I=\frac{P\times r\times t}{100}$

It is provided that:

I = $80

P = $4,000

r = 5% p.a.

Compute the time required as follows:

$I=\frac{P\times r\times t}{100}$

$t=\frac{I\times 100}{P\times r}$

$=\frac{80\times 100}{4000\times 5}\\\\=0.4\ \years\\\\=0.4\times 365\ days\\\\=146\ days$

Thus, it will take 146 days to earn an interest of $80.

4 0

2 years ago

Which are equal to 3/2?

KIM [24]

Explanation:

Starting with the first option, the square root of 12 and 8 isn’t a perfect square so it definitely can’t be reduced to 3/2.

It is the same for the second option as well.

Third option :
Root of 36 is 6
Root of 16 is 4

6/4 = 3/2

Fourth option:
Root of 81 is 9
Root of 36 is 6

9/6 = 3/2

Answer:

Therefore, the third and fourth options are the correct choices.

Hope this helped!

6 0

3 years ago

Iodine-125 has a daily decay rate of about 1%. How many milligrams of a 500 mg sample will remain after 300 days? Round the answ

Amanda [17]

So.. in this case, the starting amount is the 500mg sample... and the rate of decay, negative rate, is 1%, and at the time, the elapsed days is 0, to t = 0, P = 400

$\bf \qquad \textit{Amount for Exponential change}\\\\
A=P(1\pm r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{starting amount}\to &500\\
r=rate\to 1\%\to \frac{1}{100}\to &0.01\\
t=\textit{elapsed period}\to &300\\
\end{cases}
\\\\\\
A=500(1-0.01)^{300}$

7 0

2 years ago

Read 2 more answers

The electrical charge on a metal plate is given

Katarina [22]

Answer:

after 10 seconds the charge is 1.624

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one.

The electrical charge on a metal plate is given by the function below, where t is the time in seconds. What is the charge after 10 seconds?

C (t) = 12 $e^{\frac{-t}{5} }$