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notsponge [240]
2 years ago
9

If you pay for $48.02 item with a $50 how much change will you get back?

Mathematics
2 answers:
11111nata11111 [884]2 years ago
7 0

Answer:

$1.98

Step-by-step explanation:

50 - 48.02 = 1.98

mezya [45]2 years ago
4 0

Answer: 2 dollars

Step-by-step explanation: i think im bad at money wait why did i even awnser lol

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Which graph represents an function?
Vsevolod [243]
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5 0
3 years ago
I'm not sure about this one
Pavlova-9 [17]

Answer:

D

Step-by-step explanation:

V= 4/3\pir^3

V= 4/3\pi(9)^3

V= 3,052.08 in^3

you are correct!

7 0
3 years ago
Read 2 more answers
Number 7 and 8 plz answer quickly
Flauer [41]

(7) m∠A = 52°

(8) m∠B = 117°

Solution:

(7) Let us first define the supplementary and complementary angles.

Supplementary angles: Two angles are said to be supplementary angles if their sum is add up to 180°

Complementary angles: Two angles are said to be complementary angles if their sum is add up to 90°

Given supplement of 142° = 180° – 142°

                                           = 38°

Complement of ∠A = Supplement of 142°

⇒ Complement of ∠A = 38°

Measure of ∠A = 90° – 38°

                          = 52°

Hence m∠A = 52°.

(8) Given complement of 27° = 90° – 27°

                                                 = 63°

Supplement of ∠B = Complement of 27°

⇒ Supplement of ∠B = 63°

Measure of ∠B = 180° – 63°

                          = 117°

Hence m∠B = 117°.

3 0
4 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

P = 87\^x + 75\^y ft

6 0
3 years ago
A 2.5 X 4<br> 0.1<br> 1<br> 10<br> 100
Scilla [17]

Answer:

i think 100.277525

3 0
3 years ago
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