Answer:
242/27
Step-by-step explanation:
Using the formula for the sum, you can fill in the given values and do the arithmetic.
Sn = a1·(r^n -1)/(r -1)
S5 = 6·((1/3)^5 -1)/(1/3 -1) = 6(-242/243)/(-2/3) = 6·(121/81)
S5 = 242/27
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Or, you can write the terms and add them up. The sum is ...
6 + 2 + 2/3 + 2/9 + 2/27 = (162 +54 +18 +6 +2)/27 = 242/27
Answer:12
Step-by-step explanation:
You would know because for example, if it's out of 4 and the fraction said 4/4, that would mean one. 3/3 would mean one. 2/2 and so on
We are to find how long will it take to return to the ground?
Answer:
t = 0.48 sec
Step-by-step explanation:
We are given;
initial velocity; vi = 40 ft/s
hi = 70 ft
acceleration due to gravity; a = 32 ft/s²
Now, we are given that the rocket's height as a function of time is;
h = -12at² + vit + hi
At ground, h = 0
Plugging in the relevant values to obtain ;
0 = -12(32)t² + 40t + 70
-384t² + 40t + 70 = 0
The roots of the equation gives; t = 0.48 sec
Answer:
from what i see i see thats its D
if not im sorry but i hope i got it right
Step-by-step explanation:
