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defon
3 years ago
11

The energy needs of an eagle range between 350-600 calories per day. If it gets 120 calories from consuming 1 snake, how many sn

akes can it have
Mathematics
2 answers:
Alexxx [7]3 years ago
7 0

Answer:

  • 3- 5 snakes

Step-by-step explanation:

One snake gives 120 calories, so 3 snakes = 360 and 5 snakes = 600 calories.

The eagle can have 3 - 5 snakes per day

vladimir2022 [97]3 years ago
7 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The required number of snakes is ~

  • 3 \:  \:  to \:  \: 5 \:  \:  \: snakes

\large \boxed{ \mathfrak{Explanation}}

Minimum number of snakes that the eagle need to eat to maintain its energy level ~

  • \dfrac{350}{120}

  • \dfrac{35}{12}

  • \approx3

Maximum number of snakes that the eagle should eat to maintain the level of energy ~

  • \dfrac{600}{120}

  • 5

So,

The Eagle should have 3 - 5 snakes per day ~

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The standard IQ test has a mean of 97 and a standard deviation of 17. We want to be
densk [106]

Let's call our estimate x. It will be the average of n IQ scores. Our average won't usually exactly equal the mean 97.  But if we repeated averages over different sets of tests, the mean of our estimate the average would be the same as the mean of a single test,

μ = 97

Variances add, so the standard deviations add in quadrature, like the Pythagorean Theorem in n dimensions.  This means the standard deviation of the average x is

σ = 17/√n

We want to be 95% certain

97 - 5 ≤ x ≤ 97 + 5

By the 68-95-99.7 rule, 95% certain means within two standard deviations. That means we're 95% sure that

μ - 2σ ≤ x ≤ μ + 2σ

Comparing to what we want, that's means we have to solve

2σ = 5

2 (17/√n) = 5

√n = 2 (17/5)

n = (34/5)² = 46.24

We better round up.

Answer: We need a sample size of 47 to be 95% certain of being within 5 points of the mean

6 0
3 years ago
4p – 3 = 13<br><br><br><br> answer pls
Galina-37 [17]
P = 4

13 + 3 = 16
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These questions require reverse order, you have to work backwards
For example 4 * P you would do 4/P instead
8 0
3 years ago
Read 2 more answers
Find a center of mass of a thin plate of density delta equals 5δ=5 bounded by the lines y equals xy=x and x equals 0x=0 and the
kow [346]

Answer:

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X = \frac{my}{m} = \frac{28}{19}

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Step-by-step explanation:

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parabola ; y = 20 - x^2

attached below is the detailed solution

M = \frac{152}{3}б

Mx =  \frac{6976}{15}б

My = \frac{224}{3}б

X = \frac{my}{m} = \frac{28}{19}

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3 years ago
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Fourth, you just need to know your conversion factors.
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8 0
3 years ago
Express the sum of 3x^2+5x-6 and -x^2+3×+9?
djverab [1.8K]
I hope this helps you



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