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3 years ago

I really don't get this type of math so can someone please help me with this thank you

Mathematics

1 answer:

solmaris [256]3 years ago

5 0

The area for a trapezoid is A=1/2(b*1+b*2)h
Your base is your two parallel sides, and your parallel sides in this case is 5cm and 11cm, so that means your bases are 5&11. Your height is 4.
A=1/2(5+11)4
In order to do this you need to do the distributive property first.
1/2 x 5 = 2 1/2
1/2 x 11 = 5 1/2
Then next you need to do:
2 1/2 + 5 1/2 = 8
The last step is to do:
8 x 4 = 32
SO THE ANSWER IS 32.

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Which is the correct solution to the cubic equation, 3x+2 = -1

Effectus [21]

Answer:

= − 1

Step-by-step explanation:

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3 years ago

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How is the sum expressed in sigma notation? 11 + 17 + 23 + 29 + 35 + 41

Ann [662]

<h3>The sum expressed in sigma notation is:</h3>

$11+17+23+29+35+41=\sum\limits_{i=1}^{6}5+6i$

Solution:

Given that,

11 + 17 + 23 + 29 + 35 + 41

We have to express the sum in sigma notation

Analyse the series

5 + 6(1) = 11

5 + 6(2) = 17

5 + 6(3) = 5 + 18 = 23

5 + 6(4) = 5 + 24 = 29

5 + 6(5) = 5 + 30 = 35

5 + 6(6) = 5 + 36 = 41

Thus the series goes on like this:

5 + 6(n) , where n = 1 to 6

This can be expressed in sigma notation as:

$11+17+23+29+35+41=\sum\limits_{n=1}^{6}5+6n$

We can expand the sigma notation and verify the results

$\sum\limits_{i=1}^{6}5+6i=(5+6(1))+(5+6(2))+(5+6(3))+(5+6(4))+(5+6(5))+(5+6(6))\\\\\\\sum\limits_{i=1}^{6}5+6i=(5+6)+(5+12)+(5+18)+(5+24)+(5+30)+(5+36)\\\\\\\sum\limits_{i=1}^{6}5+6i=11+17+23+29+35+41$

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3 years ago

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HELP ME PLS I will mark brainiest if i can! qr + r; use q = 3, and r = -6

djyliett [7]

Answer:

-24

Step-by-step explanation:

3(-6)+-6

-18+-6

-24

Hope it helps. Please mark as brainliest.

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3 years ago

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9. Ms. Barton determined that the

finlep [7]

Answer:

B. 95

Step-by-step explanation:

Plug in 8625 into the equation as c:

c = 75n + 1500

8625 = 75n + 1500

Solve for n:

7125 = 75n

95 = n

So, 95 people attended.

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3 years ago

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Consider the following function. f(x) = 2x3 + 9x2 − 24x (a) Find the critical numbers of f. (Enter your answers as a comma-separ

viktelen [127]

Answer:

(a) The critical number of $f(x)$ are $x=-4, 1$

(b)

Increasing for $(-\infty, -4)$
Decreasing for $(-4, 1)$
Increasing for $(1, \infty)$

(c)

relative maximum $(-4, 112)$
relative minimum $(1, -13)$

Step-by-step explanation:

(a) The critical numbers of a function are given by finding the roots of the first derivative of the function or the values where the first derivative does not exist. Since the function is a polynomial, its domain and the domain of its derivatives is $(-\infty, \infty)$ . Thus:

$\frac{df(x)}{dx} = \frac{d(2x^3+9x^2-24x)}{dx} =6 x^2+18x -24\\6 x^2+18x -24=0\\\boxed{x=-4, x=1}$

(b)

A function $f(x)$ defined on an interval is monotone increasing on $(a, b)$ if for every $x_1, x_2 \in (a, b): x_1$ implies $f(x_1)$

A function $f(x)$ defined on an interval is monotone decreasing on $(a, b)$ if for every $x_1, x_2 \in (a, b): x_1$ implies $f(x_1)>f(x_2)$

Combining the domain $(-\infty, \infty)$ with the critical numbers we have the intervals $(-\infty, -4)$ , $(-4, 1)$ and $(1, \infty)$ . Note that any of the points are included, in the case of the infinity it is by definition and the critical number are never included because the function monotony is not defined in the critical points, i.e. it is not monotone increasing or decreasing. Now, let's check for the monotony in each interval, for this, we check for the sign of the first derivative in each interval. Evaluating in each interval the first derivative (one point is enough), we obtain the monotony of the function to be:

Increasing for $(-\infty, -4)$
Decreasing for $(-4, 1)$
Increasing for $(1, \infty)$

(c) From the values obtained in (a) so the relative extremum are the points $(-4, 112)$ and $(1, -13)$ . The $y$ -values are found by evaluating the critical numbers in the original function. Since the first derivative decreases after passing through $x=-4$ and increases after passing through the point $x=1$ we have:

relative maximum $(-4, 112)$
relative minimum $(1, -13)$

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4 years ago