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2 years ago

Plz help me fast urgent thank you :) 20 points

Mathematics

2 answers:

natima [27]2 years ago

6 0

Answer:

number 3 dual federalism

NeTakaya2 years ago

5 0

Answer:

I believe it is A. Cooperative Federalism

Step-by-step explanation:

The other ones don't seem applicable to the diagram

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Natalie just invited 100 guests to a party in her small house. The base of her house is a rectangle with dimensions 8m by 16m. I

Alex787 [66]

Answer:

6 units by 12 units

Step-by-step explanation:

Since the measurements in meters are multiples of 4, it makes this problem a little easier.

First you divide 8 by 4 to get 2

Then divide 16 by 4 to get 4

After that you're going to multiply 3 units by both quotients separately.

So you multiply 3 by 2 to get 6

Then you multiply 3 by 4 to get 12

So then you end up with a 6 unit by 12 unit drawing.

It's funny because I was actually looking for the answer to this problem. Sorry I was a little late

5 0

2 years ago

Find the value of x, if angle x measures 102 degrees

Over [174]

The answer is B
Have a good day!

3 0

2 years ago

Read 2 more answers

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n

Ivanshal [37]

Answer:

a) The probability that exactly 4 flights are on time is equal to 0.0313

b) The probability that at most 3 flights are on time is equal to 0.0293

c) The probability that at least 8 flights are on time is equal to 0.00586

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures.

a) The probability that exactly 4 flights are on time is =

b) The probability that at most 3 flights are on time is =

c)The probability that at least 8 flights are on time is =

<h2>Solution to the problem</h2>

a) Probability that exactly 4 flights are on time

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

$P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}$

Where $_nC_x$ is the number of different combinations of x success in n trials.

$_nC_x=\frac{x!}{n!(n-x)!}$

Hence,

$P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}$

$_9C_4=\frac{4!}{9!(9-4)!}=126$

$P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125$

b) Probability that at most 3 flights are on time

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

$P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)$

$P(X=0)=(0.5)^9=0.00195313$ . . . (the probability that all are not on time)

$P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625$

$P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125$

$P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625$

$P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\ P(X\leq 3) \approx 0.0293$

c) Probability that at least 8 flights are on time 

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

$P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586$

6 0

3 years ago

I need help help please

Nitella [24]

Answer:

I think it is b

Step-by-step explanation:

I hope this is correct

6 0

2 years ago

The area of a rectangular plank is 4500 cm². The plank was broken into two pieces, one of which is a square and the other a rect

svp [43]

Answer:

$Xs=30cm$ and $As=900 cm^{2}$

Step-by-step explanation:

At=As+Ar; A=b.h and $At=4500 cm^{2}$ , then: At=(x+120)x so

(x+120)x=4500, $x^{2} +120x-4500=0$ Applying cuadratic equation formula: $\frac{120+-\sqrt{120^{2} -4.1.-4500} }{2} =-\frac{120+-\sqrt{14400+18000} }{2}= x1=30 and x2=-150, finally Xs=30cm, and As=900cm^{2}$

3 0

3 years ago

Read 2 more answers