Lets say that the two unknown integers are

and

.
We know the following things about

and

:


And, we want to find

.
To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:

So, given what we know about the unknown integers, the previous can be written as:

We can easily solve for

:
The answer is 168.
Another approach to solve the problem is, from the two starting equations, compute the values of

and

, which are 12 and 14, and directly compute their product; however, the approach described is more elegant.
Answer:
Step-by-step explanation:
Since the box contains a cylinder, the height of the box must be gt; = cylinder height
And the area at the bottom of the box is definitely larger than the area at the bottom of the cylinder.
The area at the bottom of the cylinder is PI r squared,
If the bottom of the box is a square, then the area of the bottom is 4r^2, whereas the bottom tends to be polygon, which is equivalent to cutting the circle into equal parts by circle cutting.
So the area at the bottom of the box is
,
It follows that the volume of the box is greater than the volume of the cylinder
K = F + 459.67
Subtract K on both sides:
0 = F - K + 459.67
Subtract F on both sides:
-F = -K + 459.67
Divide each term by -1 so that the variables are positive:
F = K - 459.67
Domain: {1,2,3,5,7}
Range: {4,9,7,12}
Answer:
Arcsin(1/5) = 0.20
Arcsin(-0.34) = -0.35
Arcsin(0.6) = 0.64
Step-by-step explanation:
Using a calculator we can find the value of each expression:
Arcsin(1/5) = 0.20135792079, rounding to the nearest hundredth we have that: Arcsin(1/5) = 0.20.
Arcsin(-0.34) = -0.346916897527, rounding to the nearest hundredth we have that: Arcsin(-0.34) = -0.35
Arcsin(0.6) = 0.643501108793, rounding to the nearest hundredth we have that: Arcsin(0.6) = 0.64