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3 years ago

PLEASE HELP I WILL GIVE BRAINLIEST

Mathematics

2 answers:

ella [17]3 years ago

6 0

Answer:

C) <8,4>
Hope this helps

Sunny_sXe [5.5K]3 years ago

3 0

Answer:

8,4

Step-by-step explanation:

the figure is translated 8 units to the right and 4 up

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Need help urgently difficult but simple math equation if you get it right ill give you brainliest.

Zielflug [23.3K]

Answer:

No.

Step-by-step explanation:

Explanation below.

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3 years ago

plz help with this math thing i dont get it Create a scenario that leads to an inequality of the form ax + b > c. You can use

andriy [413]

You have to write a word problem where (a * x) + b is greater than c. One situation could start with (a * x) where a is 2, and x is another number, lets say 5. You have to multiply those and then add b, which we could say is 2, for the sake of it. Then all of those together has to be more than c, which could be 9 for this problem. Then you have to show your work and graph on a number line and all that stuff, and explain what your solution means in the context of the problem. That could be what the numbers mean in relation to others, or what a, x, b, and c are.

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3 years ago

Graph the linear equation. Find three

Elena L [17]

Answer:

Step-by-step explanation:

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3 years ago

Please help for bainlest

Natali [406]

Answer:

$\frac{5}{12}$

Step-by-step explanation:

$\frac{3}{4} -\frac{1}{3}$

Find the common denominator and multiply each side by that number

$\frac{9}{12} -\frac{4}{12}$

$\frac{5}{12}$

For bolded part in explanation: 4·3=12 3·3=9

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3 years ago

Use the method of "undetermined coefficients" to find a particular solution of the differential equation. (The solution found ma

Naddika [18.5K]

Answer:

The particular solution of the differential equation

= $\frac{-1,36,656cos5x+1,89,800 sin5x}{-1204}$ + $\frac{1}{37}185e^{6x})$

Step-by-step explanation:

Given differential equation y''(x) − 10y'(x) + 61y(x) = −3796 cos(5x) + 185e6x

The differential operator form $(D^{2} -10D+61)y(x) = −3796 cos(5x) + 185e^{6x}$

Rules for finding particular integral in some special cases:-

let f(D)y = $e^{ax}$ then

the particular integral $\frac{1}{f(D)} (e^{ax} ) = \frac{1}{f(a)} (e^{ax} ) if f(a)$ ≠ 0

let f(D)y = cos (ax ) then

the particular integral $\frac{1}{f(D)} (cosax ) = \frac{1}{f(D^2)} (cosax ) =\frac{cosax}{f(-a^2)}$ f(-a^2) ≠ 0

Given problem

$(D^{2} -10D+61)y(x) = −3796 cos(5x) + 185e^{6x}$

Particular integral:-

$P.I = \frac{1}{f(D)}( −3796 cos(5x) + 185e^{6x})$

$P.I = \frac{1}{D^2-10D+61}( −3796 cos(5x) + 185e^{6x})$

$P.I = \frac{1}{D^2-10D+61}( −3796 cos(5x) + \frac{1}{D^2-10D+61}185e^{6x})$

P.I = $I_{1} +I_{2}$

we will apply above two conditions, we get

$I_{1}$ =

$\frac{1}{D^2-10D+61}( −3796 cos(5x) = \frac{1}{(-25)-10D+61}( −3796 cos(5x) ( since D^2 = - 5^2)$ $= \frac{1}{(36-10D}( −3796 cos(5x) \\= \frac{1}{(36-10D}X\frac{36+10D}{36+10D} ( −3796 cos(5x)$