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3 years ago

Help Find the lateral area of this cone. Round to the nearest tenth.

Mathematics

2 answers:

Pavel [41]3 years ago

8 0

233.5 I just guessed but I’m sure that’s is it

nata0808 [166]3 years ago

3 0

Answer:

233.5 in²

Step-by-step explanation:

First we have to find the slant height.

5²+14²=c²

25+196=c²

221=c²

c=14.866

Now we can find the lateral area.

$\pi$ rl

$\pi$ (5)(14.866)

=233.51566

To the nearest tenth=

233.5 in²

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Find the slope of a line through each pair (8,10),(-7,14)

allochka39001 [22]

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3 years ago

Assume that the city of Dallas is in the state of Texas. Which statement is definitely NOT true?

OverLord2011 [107]

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3 years ago

PLSSSS HELPPP MEEEEEE

labwork [276]

Circumference of the smaller circle, using $C = \pi d$ , is approximately equal to 18.85 (I used the high floating point precision approximation of pi my calculator has in memory, then rounded to 2 decimal points.)

Using the formula $S = 0.2L$ , which in English says "the smaller circle's circumference is equal to 20% of the larger circle's", we can substitute the known value S: $18.85 = 0.2L$ and solve for L: $\frac{18.5}{0.2} = L, L = 92.5$ .

So the larger circle has a circumference approximately equal to 92.5 units.

5 0

3 years ago

Help (this for a friend)<br> a 62.1<br> b 117.4<br> c 122.1<br> d 164.5

kramer

Answer:

c. 122.1 cm

Step-by-step explanation:

so l * w + $\frac{\pi r^2}{2}$

since 6 cm is the diameter

6/2 = 3

the radius (or r) is 3

so 18 * 6 + $\frac{3.14 * 3*3}{y}$

108 + $\frac{3.14*9}{y}$

108 + $\frac{28.26}{2}$

108 + 14.13 = 122.13

simplified: 122.1 cm

hope this helps:)

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2 years ago

Read 2 more answers

The function f is linear. If f(2) = 2 and f(-6)=6 find f(6)

lina2011 [118]

$The\ slope-intercept\ form:y=mx+b\\\\f(2)=2\to for\ x=2\to y=2\\f(-6)=6\to for x=-6\to y=6\\\\put\ in\ equation\ of\ the\ line:\\\\ -\left\{\begin{array}{ccc}2=2m+b\\6=-6m+b\end{array}\right\ \ \ |subtract\ sides\ of\ the\ equations\\----------\\.\ \ \ -4=8m\ \ \ \ \ |divide\ both\ sides\ by\ 8\\.\ \ \ \ \boxed{m=-\frac{1}{2}}\\\\put\ m=-\frac{1}{2}\ to\ equation\ 2=2m+b:\\\\2=2\cdot(-\frac{1}{2})+b\\2=-1+b\ \ \ \ |add\ 1\ to\ both\ sides\\\boxed{b=3}\\\\\boxed{\boxed{y=-\frac{1}{2}x+3}}$

$therefore:f(x)=-\frac{1}{2}x+3\Rightarrow f(6)=-\frac{1}{2}\cdot6+3=-3+3=0\\\\Answer:\boxed{f(6)=0}$

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3 years ago