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Sladkaya [172]
3 years ago
5

Factor this: x^2-2x+8​

Mathematics
1 answer:
olga_2 [115]3 years ago
5 0

Answer: x^2-2x+8​

Step-by-step explanation:

its does not factor any more

its already in its lest form so therefore

the answer is x^2-2x+8​

Hope this helps :)

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At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
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(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

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Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

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Thus, the expected value of the temperature increase is 17.5°C.

7 0
3 years ago
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