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Komok [63]
3 years ago
10

Can someone please help me??

Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0
I’ve attached my work
Hope it helps!

nignag [31]3 years ago
5 0

Answer:

1st one is 30,

2nd one is 20,

so the 3rd one will be 30+20 so the answer is 50

Step-by-step explanation:

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HailyDenney2 I need your assistance please!
lorasvet [3.4K]

Answer:

x= 3

Step-by-step explanation:

6/4.5= 1.3

4/1.3=3

5 0
3 years ago
Find the equation line<br> (5,6), (4,7)
34kurt

Answer:

x+y=11

Step-by-step explanation:

Here we are given two coordinates through which our lines passes through. Now we are going to use the two point form to find the equation of the line.

The two point form is given as

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}

Here we are given two coordinates . Thus replacing them in the formula and simplifying it will give us the equation of the line.

\frac{y-6}{x-5}=\frac{7-6}{4-5}

\frac{y-6}{x-5}=\frac{1}{-1}

(y-6)=-(x-5)

y-6=-x+5

adding x and 6 on both sides we get

x+y=11

Hence this is our equation of the line passing through (5,6) & (4,7)

8 0
4 years ago
Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?
malfutka [58]
\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}

Hence, the correct options that apply are options A, D, E and F

7 0
1 year ago
You randomly choose one of the marbles. Without replacing the first marble, you choose a second marble. There are 4 marbles. One
BartSMP [9]
6 Possible outcomes.
this is a combination problem the order of drawing a marble is not important because red, blue would be the same outcome as blue, red. 
the combination formula is as follows.
nCr= \frac{n!}{r!(n-r)!}
plug in 4 for n and 2 for r.
nCr= \frac{4!}{2!(4-2)!} =6

7 0
3 years ago
Read 2 more answers
Explain how knowing 50×4 = 200 helps you find 500 × 400​
Leto [7]

Well, 50 x 4 = 200,  so just keep adding 0's!

50 x 4= 200

50 x 40 = 2,000

50 x 400 = 20,000

500 x 400 = 200,000

<em>Hope helps!-Aparri</em>

3 0
4 years ago
Read 2 more answers
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