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3 years ago

What do you think about Tokyo, what else can be done to make it a more better place to live?

Mathematics

2 answers:

mixer [17]3 years ago

5 0

Answer:

Tokyo is a good place for people for enjoying it is well known place that everyone know . it is a capital city of Japan to make this place better we have to planted trees and make proper dispoal of waste .make the place clean green and healthy to ensure or to make free from disease to build more industries with proper technology in this way it can be better

stiks02 [169]3 years ago

3 0

Answer:

Step-by-step explanation:

1. Clean

For Tokyo being the biggest city it is surprisingly clean! You hardly find litter, even at stations or places like Shibuya that are considered relatively dirty. Of course Japanese people like to party too but they always make sure that the streets are clean again in the morning. Interestingly enough, as I've discussed in this blog post there are hardly no trashcans in Tokyo, you are expected to take your trash home and that's what people do!

2. Everything is cute!

In other countries cute stuff is considered to be for children and isn't seen outside toy stores. In Japan cute, or kawaii is everywhere! At stations, shopping malls, billboards you will always discover Hello Kitty or what about a whole train in Pokemon style? Japanese people love to use mascots to promote anything. Cuteness can really brighten up your mood!

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Step-by-step explanation:

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Elenna [48]

1. By de Moivre's theorem,

$\left(4\left(\cos\left(\dfrac{7\pi}9\right) + i \sin\left(\dfrac{7\pi}9\right)\right)\right)^3 = 4^3 \left(\cos\left(\dfrac{21\pi}9\right) + i \sin\left(\dfrac{21\pi}9\right)\right) \\\\ ~~~~~~~~ = 64 \left(\cos\left(\dfrac{7\pi}3\right) + i \sin\left(\dfrac{7\pi}3\right)\right) \\\\ ~~~~~~~~ = 64 \left(\cos\left(\dfrac\pi3\right) + i \sin\left(\dfrac\pi3\right)\right) \\\\ ~~~~~~~~ = 64 \left(\dfrac12 + i\dfrac{\sqrt3}2\right) \\\\ ~~~~~~~~ = \boxed{32 + 32\sqrt3\,i}$

2. First write the given number in exponential/trigonometric form.

$z = 5-5\sqrt3\,i$

has modulus

$|z| = \sqrt{5^2 + \left(-5\sqrt3\right)^2} = \sqrt{100} = 10$

and since it lies in the second quadrant of the complex plane, its argument is

$\arg(z) = \pi + \tan^{-1}\left(-\dfrac{5\sqrt3}5\right) = \pi + \tan^{-1}\left(-\sqrt3\right) = \pi - \dfrac\pi3 = \dfrac{2\pi}3$

So, we have

$z = 5 - 5\sqrt3\,i = 10 e^{i2\pi/3} = 10 \left(\cos\left(\dfrac{2\pi}3\right) + i \sin\left(\dfrac{2\pi}3\right)\right)$

Now we apply de Moivre's theorem again, and make sure to account for the multivalued-ness of the exponential function. For $k\in\{0,1,2,3,4\}$ , the fifth roots of $z$ are

$z^{1/5} = 10^{1/5} e^{i(2\pi/3 + 2\pi k)/5}$

$k=0 \implies z^{1/5} = 10^{1/5} e^{i2\pi/15} = \boxed{10^{1/5} \left(\cos\left(\dfrac{2\pi}{15}\right) + i \sin\left(\dfrac{2\pi}{15}\right)\right)}$

$k=1 \implies z^{1/5} = 10^{1/5} e^{i8\pi/15} = \boxed{10^{1/5} \left(\cos\left(\dfrac{8\pi}{15}\right) + i \sin\left(\dfrac{8\pi}{15}\right)\right)}$

$k=2 \implies z^{1/5} = 10^{1/5} e^{i14\pi/15} = \boxed{10^{1/5} \left(\cos\left(\dfrac{14\pi}{15}\right) + i \sin\left(\dfrac{14\pi}{15}\right)\right)}$

$k=3 \implies z^{1/5} = 10^{1/5} e^{i20\pi/15} = \boxed{10^{1/5} \left(\cos\left(\dfrac{4\pi}3\right) + i \sin\left(\dfrac{4\pi}3\right)\right)}$ $k=4 \implies z^{1/5} = 10^{1/5} e^{i26\pi/15} = \boxed{10^{1/5} \left(\cos\left(\dfrac{26\pi}{15}\right) + i \sin\left(\dfrac{26\pi}{15}\right)\right)}$

6 0

2 years ago

What do you think about Tokyo, what else can be done to make it a more better place to live?​

What do you think about Tokyo, what else can be done to make it a more better place to live?