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3 years ago

Is there any way I can get a brainly tutor on pc and if there is how?

Mathematics

2 answers:

lora16 [44]3 years ago

6 0

Answer:

This question really shouldn't be here but Brainly doesn't have a app for the PC, only for mobile. You can only use the website for PC.

tankabanditka [31]3 years ago

3 0

You’d still have to pay for it like on a phone.

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A supervisor records the repair cost for 17 randomly selected VCRs. A sample mean of $68.83 and standard deviation of $12.17 are

amid [387]

Answer:

Step-by-step explanation:

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3 years ago

Julie spends $5.62 at the store. Micah spends 5 times as much as Julie. Jeremy spends $6.72 more than Micah. How much money does

avanturin [10]

Micah spent 28.10 dollars, Jeremy spent 34.82 dollars

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3 years ago

Find the value of x. Then find the measure of each labeled angle

34kurt

Answer:

x = 109

Top Right Angle = 109

Bottom Right Angle = 71

Step-by-step explanation:

Notice the two right angles on the left and recognize that the figure is a a quadrilateral (4 sides). That means it adds up to a total of 360 degrees.

(x-38) + x + 90 + 90 = 360

2x + 142 = 360

2x = 218

x = 109

(x - 38) = (109 - 38)

71 degrees for bottom right angle

109 for top right angle

8 0

3 years ago

Tash conducted a survey of the students in her school.

Rasek [7]

Answer:

The total number of students in the school is 750. You can use algebraic equation to calculate the number of the students. Let x be the total number of students in the school. Hope this helps.

7 0

3 years ago

A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali

Softa [21]

Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

P(Y = 3) = 0.19

Step-by-step explanation:

Let the events be:

$W =$ Wednesday

$T =$ Thursday

$F =$ Friday

$S =$ Saturday

Their corresponding probabilities are

$P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1$

Since $Y$ = number of days beyond Wednesday that it takes for both magazines to arrive(so possible $Y$ values are 0, 1, 2 or 3)

The possible number of outcomes are therefore $4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)$

The values associated for each of the outcomes are as follows:

$Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3$

The probability mass function of $Y$ is,

$P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19$

7 0

3 years ago