2 years ago

Find the value of the variables in the simplest form

Mathematics

2 answers:

Papessa [141]2 years ago

6 0

Answer:

x = 15 $\sqrt{3}$ , y = 15

Step-by-step explanation:

Using the sine and cosine ratios in the right triangle and the exact values

sin60° = $\frac{\sqrt{3} }{2}$ , cos60° = $\frac{1}{2}$ , then

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{x}{30}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

2x = 30 $\sqrt{3}$ ( divide both sides by 2 )

x = 15 $\sqrt{3}$

---------------------------------------------------------

cos60° = $\frac{adjacent}{hypotenuse}$ = $\frac{y}{30}$ = $\frac{1}{2}$ ( cross- multiply )

2y = 30 ( divide both sides by 2 )

y = 15

777dan777 [17]2 years ago

5 0

Answer:

Step-by-step explanation:

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Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly low, μ- 2σ , and the maximum val

allsm [11]

Answer:

The answer is "Option a".

Step-by-step explanation:

$n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\$

Using the binomial distribution: $\mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186$

In this the maximum value which is significantly low, $\mu-2\sigma$ , and the minimum value which is significantly high, $\mu+2\sigma$ , that is equal to: